Question

首先，我使用以下内容从mysql数据库获取所有数据：

$query = "SELECT * FROM locations";
    $result = mysqli_query($link,$query);
    while($row = mysqli_fetch_array($result)) {
    $locations[] = $row;
}

我有map.js文件，其中有标记数组：

markersData = {
        'locations': [
        {
            type_point: 'TravelGuide',
            location_latitude: 45.39579812501628,
            location_longitude: 14.801673889160156,
            map_image_url: 'img/thumb_map_must_8.jpg',
            name_point: 'TravelGuide',
            description_point: 'Palazzo Strozzi 9, Florence',
            get_directions_start_address: '',
            phone: '+3934245255',
            },
        {
            type_point: 'TravelGuide',
            location_latitude: 45.39579812501628,
            location_longitude: 14.801673889160156,
            map_image_url: 'img/thumb_map_must_8.jpg',
            name_point: 'TravelGuide',
            description_point: 'Palazzo Strozzi 9, Florence',
            get_directions_start_address: '',
            phone: '+3934245255',
            }

我想要的是用php数组填充此数组，但我需要使用foreach，因此我可以根据需要加载任意数量的位置。所以它会是这样的：

type_point: 'TravelGuide',
        location_latitude: $all['coordlat'],
        location_longitude: $all['coordlng'],

foreach($locations as $all)

其中一个阵列就是这个

[ {"id":"98",
   "ime1":"TravelGuide",‌
   "i‌me2":"TravelGuide",
   "adresa":"",
   "email":"",
   "mobitel":"(+385) --____",
   "telefon":"(0__) -",
   "koordinate":"45.39579812501628, 14.801673889160156",
   "kategorija":"Apartman",
   "opis1":"Proba za travelguide",
   "opis2":"Travelguide test",
   "aktivno":"1",
   "photo":"gen‌eric.jpg"
  }
 ]

使用php数组和foreach填充javascript数组

0 个答案: