select uc.adminid, count(*)
from Users uc
join UsersMessage ucm on uc.admincallid = ucm.admincallid
where uc.CallDate between '2016-08-01' and '2016-09-01' and ucm.type = 4
group by uc.adminid
order by count(*)
以下是我的尝试:
public static Dictionary<int, int> ReturnSomething(int month)
{
Dictionary<int, int> dict = new Dictionary<int, int>();
using (DataAccessAdapter adapter = new DataAccessAdapter())
{
LinqMetaData meta = new LinqMetaData(adapter);
dict = (from uc in meta.Users
join ucm in meta.meta.UsersMessage on uc.AdminCallId equals ucm.AdminCallId
where ucm.type == 4 && uc.CallDate.Month == month
group uc by uc.AdminId into g
select new { /* ???? adminid = g. */ }).ToDictionary(x => new Dictionary<int, int>(/* ????? x, x.Name*/));
}
return dict;
}
我怎样才能实现我的需要?
答案 0 :(得分:2)
字典的键是GroupBy
的键,值是Count()
,所以你需要:
// ...
.ToDictionary(g => g.Key, g => g.Count()); // key is AdminCallId and value how often this Id occured
因为您已经询问如何订购它降序:
您正在构建一个没有顺序的字典(好吧,它应该是:它是非确定性的)。所以排序是 完全没必要。它为什么无序? Read this
但是,如果你想创建其他东西并想知道如何通过Count DESC
订购,你可以使用它:
from uc in meta.Users
join ucm in meta.meta.UsersMessage on uc.AdminCallId equals ucm.AdminCallId
where ucm.type == 4 && uc.CallDate.Month == month
group uc by uc.AdminId into g
orderby g.Count() descending
select new { adminid = g.Key, count = g.Count() })