我使用非阻塞套接字来接收新连接。但是代码反复失败了accept()
。
int sockfd = ::socket(family, SOCK_STREAM | SOCK_NONBLOCK | SOCK_CLOEXEC, IPPROTO_TCP);
::bind(sockfd, bind_addr, static_cast<socklen_t>(sizeof(struct sockaddr_in6)));
ret = ::listen(sockfd, SOMAXCONN);
while (True) {
::poll(&*pollfds_.begin(), pollfds_.size(), timeoutMs);
struct sockaddr_in6 addr;
bzero(&addr, sizeof addr);
socklen_t addrlen = static_cast<socklen_t>(sizeof *addr);
int connfd = ::accept4(sockfd, sockaddr_cast(addr),
&addrlen, SOCK_NONBLOCK | SOCK_CLOEXEC);
}
errno
是EAGAIN
。
答案 0 :(得分:2)
从联机帮助页到accept(2)
:
EAGAIN或EWOULDBLOCK
套接字标记为非阻塞,并且不存在要接受的连接。 POSIX.1-2001允许在这种情况下返回错误,并且不要求这些常量具有相同的值,因此便携式应用程序应检查这两种可能性。
这意味着在客户端连接之前调用accept
。
答案 1 :(得分:1)
在致电accept
之前,您必须致电listen
和bind
。
但是由于您的套接字没有阻塞,您应该等待客户端等待连接。您可以使用select
函数执行此操作:
int sockfd = ::socket(family, SOCK_STREAM | SOCK_NONBLOCK | SOCK_CLOEXEC, IPPROTO_TCP);
// addr is for accept call, sin for bind call
struct sockaddr_in6 addr, sin;
bzero(&addr, sizeof addr);
// prepare sin to tell bind to listen on any connection on given port
sin.sin6_family = family;
sin.sin6_addr = in6addr_any;
sin.sin6_port = htons(port); // choose port on which client could connect
sin.sin6_scope_id = 0;
// bind socket to interface
if (::bind(sock, (struct sockaddr*) &sin, sizeof(sin)) < 0)
{
perror("bind");
}
// listen for new connection
if (::listen(sock, SOMAXCONN) < 0)
{
perror("socket");
}
while (1)
{
fd_set conset;
FD_ZERO(&conset);
FD_SET(sockfd, &conset);
struct timeval timeout = {10, 0};
int maxfd = sockfd;
// wait for new client
select(maxfd + 1, &conset, NULL, NULL, &timeout);
if (FD_ISSET(sockfd, &conset))
{
// a new client is waiting
int connfd = ::accept(sockfd, &addr);
if (connfd < 0)
{
perror("accept");
}
else
{
// do thing with new client
}
}
else
{
printf("no new client in last 10 seconds")
}
}