Question

public class TestScript {

    protected WebDriver driver;


@Before
    public void setUp() throws MalformedURLException {

        driver = new FirefoxDriver();


        driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);
        driver.manage().timeouts().pageLoadTimeout(60, TimeUnit.SECONDS);
        driver.manage().timeouts().setScriptTimeout(20, TimeUnit.SECONDS);

        driver.manage().deleteAllCookies();

        driver.manage().window().maximize();

        driver.navigate().to(new URL("http://www.saksfifthavenue.com"));

    }

 @Test

    public void Test1(){



       String currentWindow = driver.getWindowHandle(); 
//even without using windowhandle the same thing happens. can't locate the popup

        WebElement closePopUp = driver.findElement(By.xpath("//div[1][@id='close-button']"));
        closePopUp.click();

    }

    @After
    public void tearDown(){

        driver.close();
        driver.quit();

    }

}

Answer 1

出现的弹出窗口是模态而不是窗口，因此您无需获取windowHandle。此外，关闭窗口的xpath不正确。使用id定位关闭按钮，如下所示：

WebElement closePopUp = driver.findElement(By.id("closeButton"));
closePopUp.click();

首选使用Id和Css选择器来定位元素。此外，在旁注窗口上，如果您需要切换到窗口或获取该窗口的详细信息，则使用手柄。

希望这有帮助。

Answer 2

试试这段代码：

    // Checking Alert is present and switchTo;
    Alert alert = new WebDriverWait(driver,30).until(ExpectedConditions.alertIsPresent());
    // Dismiss alert - this will close the alert
    alert.dismiss();
    //Switching to default content after alert is closed
    driver.switchTo().defaultContent();

使用selenium webdriver junit test自动执行saksfifthavenue.com时无法关闭弹出窗口

2 个答案: