此Meteor React代码产生浏览器控制台错误:
警告:ListItems(...):必须返回有效的React元素(或null)。您可能已返回undefined,数组或其他一些无效对象。
Tracker重新计算功能的例外:
知道为什么吗?感谢
//myList.jsx
import React from 'react';
const renderIfData = (listItems) => {
if (listItems && listItems.length > 0) {
return listItems.map((item) => {
return <li key={item._id}>{item.car}</li>;
});
} else {
return <p> No cars yet!</p>
}
};
export const ListItems = ({listItems}) => {
<ol>{renderIfData(listItems)}</ol>
};
//cars.jsx
import React from 'react';
import ReactDOM from 'react-dom';
import { composeWithTracker } from 'react-komposer';
import { ListItems } from '../imports/ui/myList.jsx';
import { CarsCol } from '../imports/api/collections.js';
const composer = (props, onData) => {
const sub = Meteor.subscribe('carsCol');
if (sub.ready()) {
const cars = CarsCol.find().fetch();
onData(null, {cars});
}
};
const Container = composeWithTracker(composer) (ListItems);
ReactDOM.render(<Container />, document.getElementById('react-root'));
答案 0 :(得分:1)
除了这部分外,一切看起来都不错:
return listItems.map((item) => {
return <li key={item._id}>{item.car}</li>;
});
此操作的结果是一个元素数组,并且React会严格阻止它与您收到的错误类型。事实上,在React 16中,他们承诺允许这样做,但你可能会使用15版。无论如何,我建议在任何地方返回一个根元素,所以整个事情看起来像
//myList.jsx
import React from 'react';
export const ListItems = ({listItems}) => {
if (listItems && listItems.length > 0) {
return (
<ol>
{listItems.map((item) => (
<li key={item._id}>{item.car}</li>
))}
</ol>
);
} else {
return (
<p>No cars yet!</p>
);
}
};
//cars.jsx
import React from 'react';
import ReactDOM from 'react-dom';
import { composeWithTracker } from 'react-komposer';
import { ListItems } from '../imports/ui/myList.jsx';
import { CarsCol } from '../imports/api/collections.js';
const composer = (props, onData) => {
const sub = Meteor.subscribe('carsCol');
if (sub.ready()) {
const cars = CarsCol.find().fetch();
onData(null, {cars});
}
};
const Container = composeWithTracker(composer) (ListItems);
ReactDOM.render(<Container />, document.getElementById('react-root'));