我试图执行这个查询,但它不work.Kindly帮我这个解决方案我要选择对从子查询相关的职位最高的1图像与左连接
SELECT DISTINCT tblAdvertisement.AdvID,
tblAdvertisement.CityName,
tblAdvertisement.Model,
tblAdvertisement.Year,
tblAdvertisement.Mileage,
tblAdvertisement.imgPath,
tblAdvertisement.Price,
tblAdvertisement.VoteScore,
tblLike.isLike
FROM tblAdvertisement
LEFT JOIN tblimg
(
SELECT TOP 1
ImgPath
FROM tblimg ) AS
ON tblAdvertisement.AdvID = tblimg.AdvID
LEFT JOIN tblLike
ON tblAdvertisement.AdvID = tblLike.AdvID
AND tblAdvertisement.UserID = @userID
ORDER BY AdvID DESC
答案 0 :(得分:5)
您需要使用<script src="https://www.gstatic.com/charts/loader.js"></script>
<div id="example_scatter_chart"></div>
:
OUTER APPLY
请注意,如果您需要SELECT DISTINCT A.AdvID,
A.CityName,
A.Model,
A.Year,
A.Mileage,
I.imgPath,
A.Price,
A.VoteScore,
L.isLike
FROM tblAdvertisement A
OUTER APPLY ( SELECT TOP 1
ImgPath
FROM tblimg
WHERE AdvID = A.AdvID
ORDER BY SomeColumnToOrderBy) I
LEFT JOIN tblLike L
ON A.AdvID = L.AdvID
AND A.UserID = @userID
ORDER BY A.AdvID DESC;
图片,则应该执行TOP 1
,否则您将获得一些任意行而不是您想要的那一行。