Question

我正在尝试学习如何使用正则表达式来解析位置/地址字符串。不幸的是，我给出的数据与大多数地址的编写方式不一致和不同步。下面是我到目前为止，我遇到的问题是我需要多次解析字符串以使其达到正确的格式。

以下面的字符串为例：102 Spruce, 108 Spruce, 110 Spruce, Greenwood, SC 29649我想要的最终结果是110 Spruce, Greenwood, SC 29649

CODE：

l = nil
location_str = "102 Spruce, 108 Spruce, 110 Spruce, Greenwood, SC 29649"
1.upto(4).each do |attempt|
  l = Location.from_string(location_str)
  puts "TRYING: #{location_str}"
  break if !l.nil?
  location_str.gsub!(/^[^,:\-]+\s*/, '')
end

输出：

TRYING: 102 Spruce, 108 Spruce, 110 Spruce, Greenwood, SC 29649
TRYING: , 108 Spruce, 110 Spruce, Greenwood, SC 29649
TRYING: , 108 Spruce, 110 Spruce, Greenwood, SC 29649
TRYING: , 108 Spruce, 110 Spruce, Greenwood, SC 29649

预期：

TRYING: 102 Spruce, 108 Spruce, 110 Spruce, Greenwood, SC 29649
TRYING: 108 Spruce, 110 Spruce, Greenwood, SC 29649
TRYING: 110 Spruce, Greenwood, SC 29649

Answer 1

这是其中之一，而不仅仅是一种方式。这是另一个：

def address_from_location_string(location)
  *_, address, city, state_zip = location.split(/\s*,\s*/)
  "#{address}, #{city}, #{state_zip}"
end

address_from_location_string("102 Spruce, 108 Spruce, 110 Spruce, Greenwood, SC 29649")
# => "110 Spruce, Greenwood, SC 29649"

Answer 2

假设格式为：

Calendar c = Calendar.getInstance();
int hours = c.get(Calendar.HOUR_OF_DAY);
int minutes = c.get(Calendar.MINUTE);
int seconds = c.get(Calendar.SECOND);

if(hours*3600 + minutes*60 + seconds < 1800){
    // Day changed since last task
}

然后你只需要使用美元符号锚定到字符串的末尾来获取最后3个部分：

"Stuff you aren't interested in, more stuff, more stuff, etc., house, city, state zip"

Answer 3

没有正则表达式的尝试：

address = "102 Spruce, 108 Spruce, 110 Spruce, Greenwood, SC 29649"
elements = address.split(",").map(&:strip)
city, state_and_zip = elements[elements.length-2..-1]
addresses = elements[0...elements.length-2]

p [addresses.last, city, state_and_zip].join(",")

输出：

"110 Spruce,Greenwood,SC 29649"

正则表达式解析地址

CODE：

输出：

预期：

3 个答案: