将此jekyll代码转换为PHP的最有效方法是什么?
{% for post in site.posts limit: 12 %}
<a href="{{post.url}}" style="background-image: url(assets/img/posts/thumbnails/{{post.thumbnail}})" class="academic-thumb">
<div class="academic-meta">
<div class="name">
{{post.title}}
</div>
</div>
</a>
{% endfor %}
答案 0 :(得分:1)
<?php
foreach ($site->getPosts() as $post) {
echo '
<a href="'. $post->getUrl() .'" style="background-image: url(assets/img/posts/thumbnails/'. $post->getThumbnail() .')" class="academic-thumb">
<div class="academic-meta">
<div class="name">
'. $post->getTitle() .'
</div>
</div>
</a>';
}
这当然只有在$ post对象可用且已收集变量时才有效。
你还应该听@borracciaBlu:首先研究ruby语法和php语法