Question

以下是开始的代码：

*<?php
    $sql_query = "SELECT * FROM DistributorCourses WHERE Distributor = '". $Distributor ."'";
    $result = mysqli_query($dbconfig, $sql_query);
    $row = mysqli_fetch_array($result, MYSQLI_ASSOC);
    $count = mysqli_num_rows($result);

    echo '<div class="row">';
        echo '<div class="col-md-12">';
            echo '<table class="table">';
            if($count > 1) {
                echo '<tr>';
                    echo '<th>Course Title</th> ';
                    echo '<th>Price</th>';
                    echo '<th>Purchase</th>';
                echo '</tr>';
                while ($row = mysqli_fetch_array($result)) {
                    echo '<tr>';
                        echo '<td>'. $row['Title'] .'</td> ';
                        echo '<td>'. $row['Price'] .'</td> ';
                        if ($row['Title'] == $course && in_array("". $row['Title'] ."", $descriptions)) {
                            echo '<td><a href="#" title="Retake Exam" class="btn btn-warning">Retake Exam</a></td>';
                        }

                        elseif (in_array("". $row['Title'] ."", $descriptions)) {
                            echo '<td><a href="#" title="You have already purchased this course!" class="btn btn-default" style="background: #e6e6e6; border: 1px solid #adadad; cursor: default;">You have already purchased this course!</a></td>';
                        }

                        else {
                            echo '<td><a href="purchase.php?courseid='. $row['CourseID'] .'&title='. $row['Title'] .'" title="" class="btn btn-success">Purchase Course</a></td>';
                        }
                    echo '</tr>';
                }
            }
            echo '</table>';
        echo '</div>';
    echo '</div>';
?>*

这段代码非常出色但是......第一个elseif语句不起作用，我不明白为什么。任何人都可以找出原因吗？

我有一个$descriptions的数组，如果课程标题($row['Title'])在$descriptions中，我希望这样做，以显示＆＃34;重新考试＆＃34;如图所示。目前它仍然说“你已经购买了这门课程！”＃。＃。

$sql_query = "SELECT * FROM CustomisePage WHERE Distributor = '$Distributor'";
$result = mysqli_query($dbconfig, $sql_query);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
$count = mysqli_num_rows($result);

if($count == 1) {
    $Image = $row['Image'];
    $ImageAlt = $row['ImageAlt'];
    $headercolour = $row['headercolour'];
    $footercolour = $row['footercolour'];
}

$sql_query1 = "SELECT order_description FROM single_user_orders WHERE username = '". $_SESSION['login_user'] ."'";
$result1 = mysqli_query($dbconfig, $sql_query1);
$count1 = mysqli_num_rows($result1);

if($count1 >= 1) {
    while ($row1 = $result1->fetch_assoc()) {
        $descriptions[] = $row1['order_description'];
    }
}

$sql_query2 = "SELECT pass_or_fail, course FROM single_user_exam_results WHERE user_on_course = '". $_SESSION['login_user'] ."'";
$result2 = mysqli_query($dbconfig, $sql_query2);
$count2 = mysqli_num_rows($result2);

if($count2 >= 1) {
    while ($row2 = $result2->fetch_assoc()) {
        $passfail[] = $row2['pass_or_fail'];
        $course[] = $row2['course'];
    }
}

Answer 1

如果我看到这个，你说$ course是一个数组。就像你之后做的一样，这样做。

自：

if ($row['Title'] == $course && in_array("". $row['Title'] ."", $descriptions)) {

要：

if (in_array($row['Title'], $course) && in_array($row['Title'], $descriptions)) {

那可以做到。

我使用if，elseif和其他错误吗？

1 个答案: