Question

如何在python中实现自动过期的变量？例如，让程序运行一个小时。我想实现一个包含6个变量的数组，数组中的每个变量将在10分钟后自动删除。 1小时后，阵列中将没有变量。

Answer 1

嗯，看起来很奇怪，但可能。

听起来你需要一个记录调用__init__的时间的类。然后，实现__getitem__以检查调用它的时间，并且只有在不太晚的情况下才返回该项目。（这可能比让一个“在后台运行”的过程更容易，即使你没有要求它也会主动删除项目。）

Answer 2

我实际上必须为字典做这个。也许你会发现代码很有用：

"""Cache which has data that expires after a given period of time."""
from datetime import datetime, timedelta

class KeyExpiredError(KeyError): pass 

def __hax():
    class NoArg: pass
    return NoArg()
NoArg = __hax()

class DataCache(object):
    def __init__(self, defaultExpireTime=timedelta(1, 0, 0), dbg=True):
        self.defaultExpireTime = defaultExpireTime

        self.cache = {}
        self.dbg = dbg

        self.processExpires = True

    def setProcessExpires(self, b):
        self.processExpires = b

    def __getitem__(self, key):
        c = self.cache[key]

        n = datetime.now()
        if (n - c['timestamp']) < c['expireTime'] or not self.processExpires:
            return c['data']

        del self.cache[key]

        if self.dbg:
            print "DataCache: Key %s expired" % repr(key)

        raise KeyExpiredError(key)

    def __contains__(self, key):
        try:
            self[key]
            return True
        except KeyError:
            return False

    def __setitem__(self, key, val):
        self.cache[key] = {
            'data': val,
            'timestamp': datetime.now(),
            'expireTime': self.defaultExpireTime,
            }

    def items(self):
        keys = list(self.cache)
        for k in keys:
            try:
                val = self[k]
                yield (k, val)                                             
            except:
                pass

    def get(self, key, default=NoArg, expired=NoArg):
        try:
            return self[key]
        except KeyExpiredError:
            if expired is NoArg and default is not NoArg:
                return default
            if expired is NoArg: return None
            return expired
        except KeyError:
            if default is NoArg: return None
            return default

    def set(self, key, val, expireTime=None):
        if expireTime is None:
            expireTime = self.defaultExpireTime

        self.cache[key] = {
            'data': val,
            'timestamp': datetime.now(),
            'expireTime': expireTime,
            }

    def tryremove(self, key):
        if key in self.cache:
            del self.cache[key]
            return True
        return False

    #the following you can call without triggering any expirations
    def getTotalExpireTime(self, key):
        """Get the total amount of time the key will be in the cache for"""
        c = self.cache[key]
        return c['expireTime']

    def getExpirationTime(self, key):
        """Return the datetime when the given key will expire"""
        c = self.cache[key]
        return c['timestamp'] + c['expireTime']

    def getTimeRemaining(self, key):
        """Get the time left until the item will expire"""
        return self.getExpirationTime(key) - datetime.now()

    def getTimestamp(self, key):
        return self.cache[key]['timestamp']

    def __len__(self):
        return len(self.cache)

用法：

>>> dc = DataCache(timedelta(0, 5, 0)) #expire in 5 seconds
>>> dc[4] = 3
>>> dc[4]
3
>>> import time
>>> time.sleep(5)
>>> dc[4]
DataCache: Key 4 expired
Traceback (most recent call last):
  File "<pyshell#5>", line 1, in <module>
    dc[4]
  File "datacache.py", line 35, in __getitem__
    raise KeyExpiredError(key)
KeyExpiredError: 4
>>>

Answer 3

听起来你的阵列中的项目彼此了解，因为否则它们都将同时到期。

我认为你想要创建一个列表的子类，它会在一段时间后删除它的内容。

Answer 4

你可以创建一个后台进程来检查它传递了多少时间，并且确定了正确的项目...或者如果你想创建一个列表的子类，它会在一段时间之后删除它的对象，你可以做同样的事情，只需在 init

中调用它

def __init__(self, time):
    #run subprocess to chek_espired elements

编辑：

我写了一个例子，但它可以做得更好！

class MyList(list):
    def __init__(self,elems,  expires_time):
        list.__init__(self, elems)
        self.created = time.time()
        self.expires_time = expires_time
    def __getitem__(self, index):
        t = time.time()
        print t -  self.created
        if t - self.created > self.expires_time:
            self.created += self.expires_time
            self.pop(index)
            self.__getitem__(index)
        return list.__getitem__(self, index)

ps当然，如果程序试图从空列表中获取索引，您可以轻松引发个人错误

Answer 5

import sched
import time
import threading

a = [1, 2, 3, 4, 5, 6]

scheduler = sched.scheduler(time.time, time.sleep)

def delete(_list):
    del _list[0]

for i in range(len(a)):
    scheduler.enter(60*10*i, 1, delete, (a,))

t = threading.Thread(target=scheduler.run)

t.start()

Answer 6

通过检查脚本启动时的时间间隔，您可以使用time模块每10分钟清除一次“数组”。

http://effbot.org/librarybook/time.htm上的最后一个示例指出了你正确的方向。

自动使变量失效

6 个答案: