Ruby代码跳过程序的某个部分

时间:2016-09-01 09:00:05

标签: ruby

我正在尝试运行计算器程序但由于某种原因它正在跳过代码的某些部分。这是我的整个红宝石代码:

# require yaml file

require 'yaml'
MESSAGES = YAML.load_file('calculator_messages.yml')

LANGUAGE = 'en'

def messages(message, lang='en')
  MESSAGES[lang][message]
end

def prompt(key)
  message = messages(key, LANGUAGE)  # make sure the "messages" method is declared above this line
  Kernel.puts("=> #{message}")
end

def integer?(input)
  input.to_i.to_s == input
end

def float?(input)
  input.to_f.to_s == input
end

def valid_number?(input)
  integer?(input) || float?(input)
end

def operation_to_message(op)
  word = case op
         when '1'
           'Adding'
         when '2'
           'Subtracting'
         when '3'
           'Multiplying'
         when '4'
           'Dividing'
         end
  word
end

prompt('welcome')

name = ''
loop do
  name = Kernel.gets().chomp()

  if name.empty?()
    prompt('valid_name')
  else
    break
  end
end

prompt("Hi #{name}!")

loop do # main loop
  number1 = ''
  loop do
    prompt('first_number')
    number1 = Kernel.gets().chomp()

    if valid_number?(number1)
      break
    else
      prompt('not_a_valid_number')
    end
  end

  number2 = ''
  loop do
    prompt('second_number')
    number2 = Kernel.gets().chomp()

    if valid_number?(number2)
      break
    else
      prompt('not_a_valid_number')
    end
  end

  operator_prompt = <<-MSG
  What operation would you like to perform?
  1) add
  2) subtract
  3) multiply
  4) divide
  MSG

  prompt(operator_prompt)

  operator = ''
  loop do
    operator = Kernel.gets().chomp()
    if %w(1 2 3 4).include?(operator)
      break
    else
      prompt('choose_number_range')
    end
  end

  prompt("#{operation_to_message(operator)} the two numbers")

  result = case operator
           when '1'
             number1.to_i() + number2.to_i()
           when '2'
             number1.to_i() - number2.to_i()
           when '3'
             number1.to_i() * number2.to_i()
           else
             number1.to_f() / number2.to_f()
           end

  prompt("The answer is: #{result}")
  prompt('next_step')
  answer = Kernel.gets().chomp()
  break unless answer.downcase().start_with?('y')
end

prompt('goodbye_msg')

现在,这里是它跳过的具体代码:
1.显示名称 prompt("Hi #{name}!")
2.显示添加,减去等消息

prompt("#{operation_to_message(operator)} the two numbers")

3。最后是在结果变量中打印实际答案的部分。

result = case operator
           when '1'
             number1.to_i() + number2.to_i()
           when '2'
             number1.to_i() - number2.to_i()
           when '3'
             number1.to_i() * number2.to_i()
           else
             number1.to_f() / number2.to_f()
           end

  prompt("The answer is: #{result}")

你知道为什么它会跳过这些代码吗?

1 个答案:

答案 0 :(得分:2)

问题:据我所知,您的prompt消息会尝试翻译,但可能无法找到例如“嗨,菲利克斯。”

您可以通过更改message功能

来快速检查此理论
def messages(message, lang='en')
  MESSAGES[lang][message] || "NO TRANSLATION FOUND"
end

再次观察输出。

<强>更新 由于OP证实了理论并在评论中要求“解决方案”,最便宜的可能就是这个:

def messages(message, lang='en')
  # Look up translation, default to untranslated message.
  MESSAGES[lang][message] || message
end