在JAX-WS SOAP处理程序中访问Web方法参数？

Question

我使用Java7和JAX-WS开发了一个SOAP Web服务。这是界面的摘录：

@WebService(name = "MyWebService",
            targetNamespace = "http://www.something.com")
@SOAPBinding(parameterStyle = SOAPBinding.ParameterStyle.BARE)
public interface MyWebServiceInterface
{
   @WebMethod(operationName = "handleMsg",
              action = "handleMsg")
   @Oneway
   void handleMsg(@WebParam(name = "MessageHeader",
                            targetNamespace = "http://www.something.com",
                            header = true,
                            partName = "header") 
                  MessageHeader header,
                  @WebParam(name = "MessageBody",
                            targetNamespace = "http://www.soemthing.com",
                            partName = "body") 
                  MessageType body);
}

我已经为这个Web服务实现了一个自定义SOAP处理程序（它工作正常）来做一些额外的事情。在方法handleFault(..)中，我需要访问Web方法的原始MessageHeader（请参阅上面的界面）。怎么办呢？

public class MyHandler implements SOAPHandler<SOAPMessageContext>
{
   // ...

   @Override
   public boolean handleFault(final SOAPMessageContext context)
   {
       final Boolean outbound =
          ( Boolean ) context.get( MessageContext.MESSAGE_OUTBOUND_PROPERTY );

       // handle only incoming message which do have a message set
       if ( outbound != null && !outbound.booleanValue() && context.getMessage() != null )
       {
          MessageHeader header = 
             getOriginalHeaderOfFautlyMessage();  // <-- how can this be done?
       }
   }
}

Answer 1

SOAPMessage soapMsg = context.getMessage();
SOAPEnvelope soapEnv = soapMsg.getSOAPPart().getEnvelope();
SOAPHeader soapHeader = soapEnv.getHeader();

然后你必须提取你的标题节点并取消编组。