Question

As the question suggests.

I need to randomly generate an Integer at the end of my SQL query. It is supposed to be part of a code that I have to create from existing variables.

SELECT LEFT(Var1,2) & RIGHT(Var2,1) & RND
FROM MyTable;

The method I used here generates a number that is a decimal like 0,2895625 at the end of the code. I need it to generate a whole Integer.

Thanks Again!

Answer 1

DECLARE @maxval TINYINT, @minval TINYINT
select @maxval=24,@minval=5

SELECT CAST(((@maxval + 1) - @minval) *
    RAND(CHECKSUM(NEWID())) + @minval AS TINYINT)

Use this. set @maxval and @minval according to your need.

Or try this.

SELECT CAST(RAND() * 1000000 AS INT)

Or you can try this.

 Declare @Rnd INT;

   set @Rnd = CAST(RAND() * 1000000 AS INT)
    SELECT LEFT(Var1,2) & RIGHT(Var2,1) & @Rnd
    FROM MyTable;

or

Declare @Rnd INT;

     set @Rnd = ABS(CHECKSUM(NewId())) % 10000 
        SELECT LEFT(Var1,2) & RIGHT(Var2,1) & @Rnd
        FROM MyTable;

How to randomly generate an Integer in SQL

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