Question

我正在用PHP和MYSQL创建一个视频库。该图库下方有视频缩略图和文字标题。当用户单击图像缩略图或文本标题时，它将转到另一个将显示视频及其下的标题的网页。我希望用户点击的标题与转发到视频网页时视频下显示的标题相同。如何在点击时传递缩略图下的标题，以便将其发送到其他网页？我希望点击的标题显示在视频下方。这是gallery.php的代码：

<!DOCTYPE html>
<html>
<head>
<title>Page Title</title>
</head>
<body>

<?php
$con=mysqli_connect("localhost","root","","image_display");

// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }
$result=mysqli_query($con,"select * from table1");

while($row=mysqli_fetch_array($result,MYSQLI_ASSOC)) 
   {
       $image_link = $row['imagelink'];
       $image_path = $row['image1'];
       $caption = $row['caption'];

       echo "<div id='gallery'>";
       echo "<a href=".$image_link.val=$caption" value="fixed text"><img src=".$image_path." width='150' height='150' alt='' /> <br>";
       echo $caption."</a>"; echo "</div>";

   }


?>
</body>
</html>

这是display_video.php的代码：

<!DOCTYPE html>
<html>
  <head>
    <title>PHP!</title>
  </head>

  <body>


      <?php
      $caption=$_GET['caption'];

      $embedvideo; //This will hold embed video code

       ?>

     <div id="watchvideo" align="center">
     <?php
     echo "<h1>$caption=</h1>";
     echo  $embedvideo; ?>

     <p><a href="gallery.php">Back to gallery</p>

     </div>


  </body>
</html>

Answer 1

Try this, hopefully help you:

gallery.php

<!DOCTYPE html>
    <html>
    <head>
        <title>Page Title</title>
    </head>
    <body>

        <?php

        $con = mysqli_connect("localhost","root","","image_display");

      // Check connection
        if (mysqli_connect_errno())
        {
            echo "Failed to connect to MySQL: " . mysqli_connect_error();
        }
        $result=mysqli_query($con,"select * from table1");

        while($row=mysqli_fetch_array($result,MYSQLI_ASSOC)) 
        {
            $image_link = $row['imagelink'];
            $image_path = $row['image1'];
            $caption = $row['caption'];

            echo "<div id='gallery'>";

            echo "<a href=".$image_link."?caption=".urlencode ($caption)." value='fixed text'><img src=".$image_path." width='150' height='150' alt='' /> <br>";
            echo $caption."</a>"; echo "</div>";

        }


        ?>
    </body>
    </html>

display_video.php

    <!DOCTYPE html>
<html>
<head>
  <title>PHP!</title>
</head>

<body>


  <?php
  $caption=$_GET['caption'];

  $embedvideo = "This will hold embed video code";

  ?>

  <div id="watchvideo" align="center">
   <?php
   echo "<h1>".$caption."</h1>";
   echo  $embedvideo; ?>

   <p><a href="gallery.php">Back to gallery</p>

 </div>


</body>
</html>

如何使用PHP和MYSQL将缩略图下的标题文本传递到另一个网页

1 个答案: