细分数据

Question

SELECT SUM(CASE 
            WHEN answer_time IS NOT NULL
                AND A.ent_split IS NOT NULL
                AND call_type NOT LIKE 'PBX%'
                THEN 1
            ELSE 0
            END) AS CH
    ,SUM(CASE 
            WHEN answer_time IS NOT NULL
                AND A.ent_split IS NOT NULL
                AND call_type NOT LIKE 'PBX%'
                THEN 1
            ELSE 0
            END) + SUM(CASE 
            WHEN abandon_time IS NOT NULL
                AND answer_time IS NULL
                THEN 1
            ELSE 0
            END) AS CO
FROM reporting_call_matrix AS A WITH (NOLOCK)
WHERE A.CALENDAR_DATE >= '10/01/2015'
    AND A.CALENDAR_DATE <= '4/30/2016'
    AND A.SPLIT IN (
        35
        ,55
        ,73
        )
    AND (A.ent_split IS NOT NULL)

作为回报，将所有3个拆分信息汇总到  CH 175282  CO 209452

我的问题是我需要数据来显示每个分裂IN

的个体

Answer 1

＆＃34;每个分组的数据＆＃34;听起来你需要使用imagestore。你尝试过这样的事吗？

GROUP BY