Question

如何总结重复值 <* em>（SSRS 2005）。 *

例如。我的查询返回如下值：

CusID Discount Amount
1        20      1000
1        20      2000
1         5       700
2        15      1500
2        15      3000

但是，当我在Group Footer中总计折扣金额时，我无法得到如下的总值。我得到45为CusID 1而不是25.请帮我解决这个问题。谢谢。

CusID Discount Amount
1        20      1000
1        20      2000
1         5       700
------------------------
Total    25      3700

2        15      1500
2        15      3000
------------------------
Total    15      4500

Answer 1

如果没有您的实际数据，我只能根据您提供的数据为您提供代码示例。

declare @table table (CustID int, Discount int, Amount int)


    insert into @table (CustID,Discount,Amount)
    select 1 as CusID,20 as Discount,1000 as Amount
    union all
    select 1,20,2000
    union all
    select 1,5,700
    union all
    select 2,15,1500
    union all
    select 2,15,3000

    select
        CustID,
        sum(Discount) as Discount,
        sum(Amount) as Amount
    from
    (
        select
            CustID,
            Discount,
            SUM(Amount) as Amount
        from @table
        group by CustID, Discount
    ) a
    group by CustID

Answer 2

使用总和（不同的x）

对DForcek42的答案进行了一点简化

declare @table table (CustID int, Discount int, Amount int)

insert into @table (CustID,Discount,Amount)
select 1 as CusID,20 as Discount,1000 as Amount
union all
select 1,20,2000
union all
select 1,5,700
union all
select 2,15,1500
union all
select 2,15,3000

select
    CustID,
    sum(distinct Discount),
    SUM(Amount) as Amount
from @table
group by CustID

如何对组中的重复值求和（SSRS 2005）

2 个答案: