Question

全部，

我有两个数组如下：

var arr1 = [ '1956888670', '2109171907', '298845084' ];
var arr2 = [ 
  { KEY: '1262875245', VALUE: 'Vijay Kumar Verma' },
  { KEY: '1956888670', VALUE: 'Sivakesava Nallam' },
  { KEY: '2109171907', VALUE: 'udm analyst' },
  { KEY: '298845084', VALUE: 'Mukesh Nagora' },
  { KEY: '2007285563', VALUE: 'Yang Liu' },
  { KEY: '1976156380', VALUE: 'Imtiaz Zafar' },
  ];

arr1有键，arr2有键和值。我想输出arr1中存在的那些键的键和值。因此我的输出应该是，

[{ KEY: '1956888670', VALUE: 'Sivakesava Nallam' },
  { KEY: '2109171907', VALUE: 'udm analyst' },
  { KEY: '298845084', VALUE: 'Mukesh Nagora' },]

请求您的帮助以编写一个函数来使用javascript.Thanks提前获取所需的输出。

Answer 1

 var arr1 = [ '1956888670', '2109171907', '298845084' ];
var arr2 = [ 
  { KEY: '1262875245', VALUE: 'Vijay Kumar Verma' },
  { KEY: '1956888670', VALUE: 'Sivakesava Nallam' },
  { KEY: '2109171907', VALUE: 'udm analyst' },
  { KEY: '298845084', VALUE: 'Mukesh Nagora' },
  { KEY: '2007285563', VALUE: 'Yang Liu' },
  { KEY: '1976156380', VALUE: 'Imtiaz Zafar' },
  ];


  result = arr2.filter( function(obj) {
    return arr1.indexOf(obj.KEY) >= 0;
  });

  console.info(result);

Answer 2

您可以尝试使用filter - Array.prototype.filter()：

var output = arr2.filter(function(item) {
  return arr1.indexOf(item.KEY) >= 0;
});

Answer 3

您可以使用Set进行过滤。

var arr1 = ['1956888670', '2109171907', '298845084'],
    arr2 = [{ KEY: '1262875245', VALUE: 'Vijay Kumar Verma' }, { KEY: '1956888670', VALUE: 'Sivakesava Nallam' }, { KEY: '2109171907', VALUE: 'udm nalyst' }, { KEY: '298845084', VALUE: 'Mukesh Nagora' }, { KEY: '2007285563', ALUE: 'Yang Liu' }, { KEY: '1976156380', VALUE: 'Imtiaz Zafar' }],
    mySet = new Set,
    result;

arr1.forEach(function (a) {
    mySet.add(a);
});

result = arr2.filter(function (a) {
    return mySet.has(a.KEY);
});

console.log(result);

通过字符串数组从对象数组中搜索以获取对象数组

3 个答案: