I want to retrieve a random emoji inside the range.
let emojiRanges = [
0x1F601...0x1F64F,
0x1F680...0x1F6C0,
]
let flattenEmoji = emojiRanges.flatten()
// the loop for emoji works
for i in flattenEmoji {
let st = String(format:"0x%2X %@", i, String(UnicodeScalar(i)))
print(st)
}
// but this is not possible to obtain value at wanted index
//there is a compiler error:
let randomSign = String(UnicodeScalar(flattenEmoji[arc4random_uniform(UInt32(flattenEmoji.count))]))
print("RANDOM \(randomSign)")
the error:
ViewController.swift:68:67: Cannot subscript a value of type 'FlattenBidirectionalCollection<[Range]>' (aka 'FlattenBidirectionalCollection>>') with an index of type 'UInt32'
What is the proper way to get a result?
答案 0 :(得分:8)
问题在于flatten()
已延迟应用,因此会返回一个特殊的FlattenBidirectionalCollection
,其由FlattenBidirectionalCollectionIndex
而不是Int
编制索引。
因此,最简单的解决方案是简单地使用Array(_:)
构造函数(或flatMap(_:)
)以便急切地应用范围的展平,这将创建一个数组,然后您可以使用Int
。
let flattenEmoji = Array(emojiRanges.flatten()) // In Swift 3, flatten() is named joined()
let randomIndex = Int(arc4random_uniform(UInt32(flattenEmoji.count)))
let randomSign = String(UnicodeScalar(flattenEmoji[randomIndex]))
如果您希望延迟展开扁平化,则可以使用集合advancedBy(_:)
上的startIndex
直接下标FlattenBidirectionalCollection
(对于Swift 2):
let randomIndex = flattenEmoji.startIndex.advancedBy(Int(arc4random_uniform(UInt32(flattenEmoji.count))))
let randomSign = String(UnicodeScalar(flattenEmoji[randomIndex]))
在Swift 3中,作为collections move their indices,您需要使用集合的index(_:offsetBy:)
方法:
let randomIndex = flattenEmoji.index(flattenEmoji.startIndex, offsetBy: Int(arc4random_uniform(UInt32(flattenEmoji.count))))
答案 1 :(得分:4)
将emojiRanges
声明更改为:
let emojiRanges = Array(0x1F601...0x1F64F) + Array(0x1F680...0x1F6C0)
那么生活将变得更加容易。
for i in emojiRanges {
let st = String(format:"0x%2X %@", i, String(UnicodeScalar(i)))
print(st)
}
randomSign
中的您应该将索引转换为Int
let randomSign = String(UnicodeScalar(emojiRanges[Int(arc4random_uniform(UInt32(emojiRanges.count)))]))
print("RANDOM \(randomSign)")