Question

我正在尝试从xml中删除子节点。我的脚本正在运行..但它不会删除子节点......而不仅仅是我要删除的节点。

import groovy.xml.*; 
def employees='''<Employees>
                      <Employee>
                         <ID>123</ID>
                         <Name>xyz</Name>
                         <Addresses>
                             <Address>
                                <Country>USA</Country>
                                <ZipCode>40640</ZipCode>
                             </Address>
                          </Addresses>
                      </Employee>
                      <Employee>
                         <ID>345</ID>
                         <Name>abc</Name>
                         <Addresses>
                             <Address>
                                <Country>CA</Country>
                                <ZipCode>50640</ZipCode>
                             </Address>
                          </Addresses>
                      </Employee>
                    </Employees>''' 
def fields = ['Name','ZipCode'] 
def xml = new XmlParser().parseText(employees) 
xml.Employee.each { node -> 
     node.children().reverse().each{ 
        if(!fields.contains(it.name())) { 
            node.remove(it) 
        } 
    } 
} 

XmlUtil.serialize(xml)

如何从xml中的每个员工中删除节点ZipCode？

Answer 1

Like below:

import groovy.xml.*

def employees='''<Employees>
                      <Employee>
                         <ID>123</ID>
                         <Name>xyz</Name>
                         <Addresses>
                             <Address>
                                <Country>USA</Country>
                                <ZipCode>40640</ZipCode>
                             </Address>
                          </Addresses>
                      </Employee>
                      <Employee>
                         <ID>345</ID>
                         <Name>abc</Name>
                         <Addresses>
                             <Address>
                                <Country>CA</Country>
                                <ZipCode>50640</ZipCode>
                             </Address>
                          </Addresses>
                      </Employee>
                    </Employees>''' 
def fields = ['Name','ZipCode'] 

def xml = new XmlParser().parseText(employees) 

xml.'**'.findAll { it.name() in fields }*.replaceNode { }

XmlUtil.serialize(xml)

This checks if node name is present in the list of fields while doinf a depth first search. If present then it removes the node. In the above example, Name and ZipCode is removed.

删除XML中的子节点

1 个答案: