Question

我有以下表格列：

1）用户

Sub CreateChart()
Dim rng As Range
Set rng = ActiveSheet.Range("A4:C8")
ActiveSheet.Shapes.AddChart.Select
With ActiveChart
    .SetSourceData Source:=Range("Feuil1!$A$4:$B$8")
    .SeriesCollection.NewSeries
    .SetSourceData Source:=rng, PlotBy:=xlColumns
    .ChartType = xlBarStacked
    .SeriesCollection(1).Interior.ColorIndex = 5  'Change value to change color
    End With
End Sub

2）项目

user_id  username

3）project_status

p_id   p_name

4）公司

psdi    p_id    cdid   cid   sid  short_list   res_sent   status_date

5）状态

cid   company_name

6）projects_log

sid    status_name    status_order    is_cv_sent

现在，在此pl_id cdid project_name p_id user_id status date_time表中存在相同的projects_log值。

我想将最新p_id。的所有唯一p_id显示为DESC订单..

我正在使用以下查询，但无法获得结果。它没有向我显示所有唯一date_time作为p_id DESC顺序:(

date_time

更新：

现在使用此查询但显示错误消息：

mysqli_fetch_array（）期望参数1为mysqli_result，boolean 给定

$get_log = mysqli_query($link, "SELECT 
    pl.*, 
    u.username, 
    p.p_name, 
    c.company_name, 
    s.status_name, 
    ps.* 
    FROM projects_log AS pl 
    LEFT JOIN users AS u ON u.user_id =  pl.user_id 
    LEFT JOIN projects AS p ON p.p_id = pl.p_id     
    LEFT JOIN project_status AS ps ON ps.p_id = pl.p_id 
    LEFT JOIN company AS c ON c.cid = ps.cid 
    LEFT JOIN status AS s ON s.sid = ps.sid 
    WHERE pl.cdid = '$cdid' GROUP BY pl.p_id
    ORDER BY pl.pl_id DESC ");

更新了错误消息：

错误：重复列名称＆＃39; p_id＆＃39;警告：mysqli_fetch_array（）期望参数1为mysqli_result，布尔值为第648行的C：\ xampp \ htdocs \ dev \ frontend \ getContactDetails.php

Answer 1

尝试此查询： -

Select * from (
SELECT
    pl.pl_id,pl.cdid,pl.project_name,pl.p_id,pl.user_id,pl.status,pl.date_time,
    ps.psid,ps.cid,ps.sid,ps.short_list,ps.res_sent,ps.status_date,  
    u.username, 
    p.p_name, 
    c.company_name, 
    s.status_name, 
    pl.pl_id grp_use
    FROM projects_log AS pl 
    LEFT JOIN users AS u ON u.user_id =  pl.user_id 
    LEFT JOIN projects AS p ON p.p_id = pl.p_id     
    LEFT JOIN project_status AS ps ON ps.p_id = pl.p_id 
    LEFT JOIN company AS c ON c.cid = ps.cid 
    LEFT JOIN status AS s ON s.sid = ps.sid 
    WHERE pl.cdid = '$cdid' 
    ORDER BY pl.pl_id DESC
) as new_tab
GROUP BY new_tab.grp_use

为什么mysql order by keyword不能按预期使用GROUP by keyword？

1 个答案: