Question

我的字符串变量有这样的值

string hello = "Endpoint: Efficacy, Intervene: Single Group, Mask: Open, Purpose: Treatment";

当我从XML中提取时Endpoint，Intervene，Mask和Purpose仍然存在同样但它的价值可以改变。我想将此Endpoint，intervene，mask和purpose分别存储在不同的变量中，我们将非常感谢您的帮助。

Answer 1

使用Dictionary

尝试这种方式

        string hello = "Endpoint: Efficacy, Intervene: Single Group, Mask: Open, Purpose: Treatment";
        Dictionary<string, string> result = new Dictionary<string, string>();
        var s1 = hello.Split(',');

        foreach (var s in s1)
        {
            var v = s.Split(':');
            result.Add(v[0].Trim(), v[1].Trim());
        }

之后，您可以使用key

的value Dictionary获得结果

        foreach (var a in result)
        {
            Console.WriteLine(a.Key +" " + a.Value);
        }

Answer 2

var result = hello.Split(',')
               .Select(part => part.Split(':'))
               .ToDictionary(split => split[0], split => split[1].Trim());

Answer 3

如果模式已修复，这可以帮助您。

string hello = "Endpoint: Efficacy, Intervene: Single Group, Mask: Open, Purpose: Treatment";
string[] packs = hello.Split(',');
var data = packs.ToDictionary(k => k.Split(':').First().Trim(), v => v.Split(':').Last().Trim());

Answer 4

首先将string分割为,，然后再分类为:并将结果保存在字典中：

public class Program
{
    public static void Main(string[] args)
    {
        string hello = "Endpoint: Efficacy, Intervene: Single Group, Mask: Open, Purpose: Treatment";
        string[] arr = hello.Split(',');
        Dictionary<string, string> result = new Dictionary<string, string>();
        foreach(string s in arr)
        {
            string[] keyValuePair = s.Split(':');
            result[keyValuePair[0].Replace(" ","")] = keyValuePair[1].Replace(" ","");

        }

        foreach(var v in result)
        {
            Console.WriteLine(v.Key + " : " + v.Value );
        }


    }
}

Answer 5

我想出了一些更有活力的东西，万一有人必须处理变量关键字才能匹配。

首先提取关键字并构建匹配的模式。然后按名称捕获匹配项，每个捕获组以关键字命名，以便我们可以通过关键字访问它们：

var input = "Endpoint: Efficacy, Intervene: Single Group, Mask: Open, Purpose: Treatment";

//extract keywords: (word followed by ':' )
var keywords = Regex.Matches( input, @"(\w*):" ).Cast<Match>()
    .Select( m => m.Groups[ 1 ].Value );

//build the pattern to match (create capture groups named as keywords)
var pattern = String.Join( ", ", keywords.Select( 
    k => k + $@": (?<{k}>(\w*\s*)*)" ) );

var matches = Regex.Matches( input, pattern );

//access groups by keyword
foreach( var keyword in keywords )
    Console.WriteLine( matches[ 0 ].Groups[ keyword ].Value );

从字符串中提取子字符串

5 个答案: