Question

我必须找出在2小时之前创建并且在过去两小时内创建的记录数。我可以找到使用

[最近两小时创建]

select count(*)
 from trans_calc 
where
I_TRACKING_CODE = 112
and d_entered > (current_timestamp - 2 hours)

[在两小时之前创建]

select count(*)
 from trans_calc 
where
I_TRACKING_CODE = 112
and d_entered < (current_timestamp - 2 hours)

我们可以合并这两个sqls或者事实上我们可以编写一个可以为我们提供所需输出的sql吗？

Answer 1

试试这个：

SELECT
    SUM(CASE WHEN d_entered>(current_timestamp-2 hours) THEN 1 ELSE 0 END AS NewerCount
    ,SUM(CASE WHEN d_entered<=(current_timestamp-2 hours) THEN 1 ELSE 0 END AS OlderCount
    FROM trans_calc 
    WHERE I_TRACKING_CODE = 112

Answer 2

怎么样

SELECT CASE WHEN (d_entered > (current_timestamp - 2 hrs)
            THEN 'New'
            ELSE 'Old' AS AGE
     , Count(*) as Rows
from trans_calc 
where I_TRACKING_CODE = 112
GROUP BY CASE WHEN (d_entered > (current_timestamp - 2 hrs) THEN 'New' ELSE 'Old'

Answer 3

SELECT SUM(lasttwo) AS lasttwo, COUNT(*) - SUM(lasttwo) AS others
FROM
(
  SELECT 
      CASE WHEN d_entered > (current_timestamp - 2 hours) THEN 1 ELSE 0 END AS lasttwo 
  FROM 
      trans_calc 
  WHERE
      I_TRACKING_CODE = 112
) AS det

Answer 4

是：

在一个输出行中，

   select 
       Sum(Case When d_entered > (current_timestamp - 2 hours) 
            Then 1 Else 0 End) afterCount,
       Sum(Case When d_entered <= (current_timestamp - 2 hours) 
            Then 1 Else 0 End) beforeCount
   from trans_calc  
   where I_TRACKING_CODE = 112

或在BradC建议的两个单独的行中......

Answer 5

SELECT
    d_entered > (current_timestamp - 2 hours) AS IsRecent,
    COUNT(*)
FROM trans_calc
WHERE I_TRACKING_CODE = 112
GROUP BY IsRecent

如何将这两个sqls合二为一？

5 个答案: