我想通过过滤字符串数组来检查给定对象中是否存在值。
我想检查keys
数组中的值是否包含在我循环的JSON对象中。如果其中一个值不是,则必须执行其他操作,但前提是resArray
数组中包含不存在的值(keys
中)。
这是我尝试的内容:
var keys = [
"total_kills",
"total_deaths",
"total_planted_bombs",
"total_defused_bombs",
"total_kills_knife",
"total_kills_headshot",
"total_wins_pistolround",
"total_wins_map_de_dust2",
"last_match_wins",
"total_shots_fired",
"total_shots_hit",
"total_rounds_played",
"total_kills_taser",
"last_match_kills",
"last_match_deaths",
"total_kills_hegrenade",
];
var resArray = stats.playerstats.stats;
var statsArray = [];
for (var i = 0; i < keys.length; i++) {
for(var j = 0; j < resArray.length; j++){
//if the value in keys array exists, do something
if(resArray[j]["name"] === keys[i]){
//do something
}
if(<value doesn't exist)>)
//do something else.
}
}
function contains(obj, key, value) {
return obj.hasOwnProperty(key) && obj[key] === value;
}
var resArray = stats.playerstats.stats;
var statsArray = [];
for (var i = 0; i < keys.length; i++) {
resArray.some(function(found){
if(contains(found, "name", keys[i])){
statsArray.push(found);
}
});
if(typeof statsArray[i] == 'undefined'){
console.log("Not present in array: " + keys[i]);
statsArray.push({"name": keys[i], "value": 'None'});
}
}
感谢大家回复了这个帖子。
答案 0 :(得分:1)
您的示例暗示您根据所提供密钥的统计信息和条件存在创建新阵列。构建此数组的一种简单方法是使用Array.prototype.map
枚举您的stats数组。接下来,在每次迭代的回调中,您可以将name
属性作为参数传递给keys.indexOf
,以检查name
数组中是否存在特定的keys
。
var statsArray = stats.map(function(stat) {
if (keys.indexOf(stat.name) > -1) {
return stat;
} else {
return stat.name + ' not found.';
}
});
这将生成一个新数组,该数组将包含stat对象或不包含其在键中的缺失。但是,只要它是一个有效的数组项,你就可以回复你想要的任何东西。
这是一个包含一小部分数据集的工作示例(但可以使用原始数据集):
var keys = [
"total_kills",
"total_deaths",
"total_planted_bombs",
"total_defused_bombs",
"total_kills_knife",
"total_kills_headshot",
"total_wins_pistolround",
"total_wins_map_de_dust2",
"last_match_wins",
"total_shots_fired",
"total_shots_hit",
"total_rounds_played",
"total_kills_taser",
"last_match_kills",
"last_match_deaths",
"total_kills_hegrenade",
];
var stats = [{
"name": "total_kills",
"value": 25305
}, {
"name": "total_deaths",
"value": 27474
}, {
"name": "total_time_played",
"value": 1822419
}, {
"name": "total_planted_bombs",
"value": 1397
}, {
"name": "total_defused_bombs",
"value": 239
}, {
"name": "total_wins",
"value": 11477
}, {
"name": "total_damage_done",
"value": 3783962
}, {
"name": "total_money_earned",
"value": 65159500
}, {
"name": "total_rescued_hostages",
"value": 1
}, {
"name": "total_kills_knife",
"value": 278
}, {
"name": "total_kills_hegrenade",
"value": 168
}, {
"name": "total_kills_glock",
"value": 699
}, {
"name": "total_kills_deagle",
"value": 1289
}, {
"name": "total_kills_elite",
"value": 37
}, {
"name": "total_kills_fiveseven",
"value": 165
}, {
"name": "total_kills_xm1014",
"value": 78
}, {
"name": "total_kills_mac10",
"value": 154
}, {
"name": "total_kills_ump45",
"value": 330
}, {
"name": "total_kills_p90",
"value": 1105
}, {
"name": "total_kills_awp",
"value": 6934
}, {
"name": "total_kills_ak47",
"value": 4528
}, {
"name": "total_kills_aug",
"value": 137
}, {
"name": "total_kills_famas",
"value": 540
}, {
"name": "total_kills_g3sg1",
"value": 116
}, {
"name": "total_kills_m249",
"value": 50
}, {
"name": "total_kills_headshot",
"value": 7112
}, {
"name": "total_kills_enemy_weapon",
"value": 2308
}, {
"name": "total_wins_pistolround",
"value": 843
}, {
"name": "total_wins_map_cs_assault",
"value": 9
}, {
"name": "total_wins_map_cs_italy",
"value": 15
}, {
"name": "total_wins_map_cs_office",
"value": 11
}, {
"name": "total_wins_map_de_aztec",
"value": 71
}, {
"name": "total_wins_map_de_cbble",
"value": 373
}, {
"name": "total_wins_map_de_dust2",
"value": 4857
}, {
"name": "total_wins_map_de_dust",
"value": 25
}, {
"name": "total_wins_map_de_inferno",
"value": 777
}, {
"name": "total_wins_map_de_nuke",
"value": 247
}, {
"name": "total_wins_map_de_train",
"value": 47
}, {
"name": "total_weapons_donated",
"value": 2466
}, {
"name": "total_broken_windows",
"value": 30
}, {
"name": "total_kills_enemy_blinded",
"value": 566
}, {
"name": "total_kills_knife_fight",
"value": 67
}, {
"name": "total_kills_against_zoomed_sniper",
"value": 2284
}, {
"name": "total_dominations",
"value": 270
}, {
"name": "total_domination_overkills",
"value": 225
}, {
"name": "total_revenges",
"value": 207
}, {
"name": "total_shots_hit",
"value": 83704
}, {
"name": "total_shots_fired",
"value": 399207
}, {
"name": "total_rounds_played",
"value": 23419
}, {
"name": "total_shots_deagle",
"value": 12137
}, {
"name": "total_shots_glock",
"value": 21299
}, {
"name": "total_shots_elite",
"value": 777
}, {
"name": "total_shots_fiveseven",
"value": 3385
}, {
"name": "total_shots_awp",
"value": 22667
}];
var statsArray = stats.map(function(stat) {
if(keys.indexOf(stat.name) > -1) {
return stat;
} else {
return stat.name + ' not present in keys';
}
});
console.log(statsArray);
&#13;
答案 1 :(得分:0)
使用数组函数的组合可以实现您想要的效果。例如:
let stats = data.playerstats.stats;
let matches = stats.filter(i => keys.indexOf(i.name) >= 0);
let matchKeys = matches.map(k => k.name);
let negatives = keys.filter(i => matchKeys.indexOf(i) < 0);
然后你可以循环完成匹配/否定,以便用它们做你想做的事。
小提琴here。