所以我使用curl从API返回一些JSON,我使用<head>
<meta http-equiv="Content-Security-Policy" content="default-src 'self' data: gap: https://ssl.gstatic.com 'unsafe-eval'; style-src 'self' 'unsafe-inline'; media-src *">
<meta name="format-detection" content="telephone=no">
<meta name="msapplication-tap-highlight" content="no">
<meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width">
<link rel="stylesheet" type="text/css" href="css/index.css">
<link rel="stylesheet" type="text/css" href="css/bootstrap.css">
<link rel="stylesheet" type="text/css" href="css/bootstrap.min.css">
<title>Hello World</title>
<link type="text/css" rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.0.1/css/bootstrap.min.css" />
<style>
nav#nav1{margin-top: 24px;}
nav#nav1 > a{ background:#B9E1FF; color:#000; padding:10px; text-decoration:none; border-radius:5px; font-family:"Arial Black", Gadget, sans-serif; }
nav#nav1 > a:hover{ background: #BBEA00; }
nav#nav1 > a:active{ background: #EEFFA8; }
</style>
<script>
var bleep = new Audio();
bleep.src = 'bleep.mp3';
</script>
</head>
<body>
<div class="container">
<nav id="nav1">
<a href="#" onmousedown="bleep.play()">Home</a>
<a href="#" onmousedown="bleep.play()">About Us</a>
<a href="#" onmousedown="bleep.play()">Services</a>
<a href="#" onmousedown="bleep.play()">Contact</a>
</nav>
</div>
我已设法访问json_decode($result,true);
,但我需要遍历整个数组并输出title
,title
,url
和location
。
我正在picture
打印所有内容:
foreach
什么阻止我如何访问每个元素。
<?php
foreach ($json as $value) {
echo "<pre>";
print_r($json);
echo $json['data'][2]['title'];
}
?>
答案 0 :(得分:-1)
<?php
foreach ($json as $value) {
foreach($value['data'] as $inner){ //looping json['data']
echo $inner['id'];
echo $inner['title'];
foreach($inner['programmes'] as $in_inner){ //looping json['data']['element_number']['programmers']
echo $in_inner['id'].':'.$in_inner['short_name'];
}
}
}
?>
通过这种方式,您可以遍历内部数组。