Question

我的python代码由于某种原因不能工作。它说错误来自函数的语法，但我不确定它为什么这样做

one=1
two=2
three=3
four=4
five=5
six=6
seven=7
eight=8
nine=9
ten=10
print "test"
def convert()
  number = raw_input('Enter the number you need converted to binary')
enterYourCommand = raw_input("Enter your command")
if enterYourCommand is "convert"
  convert()
elif enterYourCommand is "tonumber"
  tonumber()

Answer 1

在函数定义之后没有:，如果是：

one=1
two=2
three=3
four=4
five=5
six=6
seven=7
eight=8
nine=9
ten=10
print "test"

def convert():
  number = raw_input('Enter the number you need converted to binary')

enterYourCommand = raw_input("Enter your command")

if enterYourCommand is "convert":
  convert()
elif enterYourCommand is "tonumber":
  tonumber()

Answer 2

您在if，elif和def之后错过了冒号。你必须缩进四个空格。有关示例，请参阅this link。

one = 1
two = 2
three = 3
four = 4
five = 5
six = 6
seven = 7
eight = 8
nine = 9
ten = 10

enterYourCommand = raw_input("Enter your command")

def convert():
    number = raw_input('Enter the number you need converted to binary')

if enterYourCommand == "convert":
    convert()
elif enterYourCommand == "tonumber":
    tonumber()

希望它有所帮助。

编辑

将is替换为==。

is将返回True
==将返回True。

资料来源：is-there-a-difference-between-and-is-in-python

Answer 3

所有python函数的声明行末尾都应该有一个冒号:。

例如：

    def convert():
        number = raw_input('Enter the number you need converted to binary')

此外，您的if和elif声明也是如此：

    if enterYourCommand is "convert":
        convert()
    elif enterYourCommand is "tonumber":
        tonumber()

所以，只需在每个声明的末尾添加:，你就应该好了。

Python语法错误与功能

3 个答案: