要转换为json的XML
ns1:UnderwritingRequest xmlns:xsd="" xmlns:xsi="" xmlns:ns1="ABCD" ResponseQueueName="">
<ns1:Header>
<ns1:TrackingId>ABCDEF</ns1:TrackingId>
<ns1:PartnerId>Myhome</ns1:PartnerId>
<ns1:ProductIdentifier>33</ns1:ProductIdentifier>
<ns1:ProductRollupId>22</ns1:ProductRollupId>
<ns1:ProductLoanClass>KYC</ns1:ProductLoanClass>
<ns1:CustomerId>123</ns1:CustomerId>
</ns1:Header>
<ns0:Application xmlns:ns0="ABCDE">
<ns0:SourceId>Web</ns0:SourceId>
<ns0:ApplicationNumber>3AAA</ns0:ApplicationNumber>
<ns0:ApplicationUniqueId>3AAA</ns0:ApplicationUniqueId>
<ns0:SubmitDate>2015-07-15</ns0:SubmitDate>
<ns0:OriginalDate>2015-07-15</ns0:OriginalDate>
<ns0:ExpirationDate>2015-07-25</ns0:ExpirationDate>
<ns0:InitialSubmitDate>2015-07-15</ns0:InitialSubmitDate>
<ns0:IsApplicationSigned>true</ns0:IsApplicationSigned>
<ns0:SignedDate>2015-07-15</ns0:SignedDate>
<ns0:IsApplicationAccepted>true</ns0:IsApplicationAccepted>
<ns0:AcceptedAmount>0</ns0:AcceptedAmount>
<ns0:DecisionType>NO</ns0:DecisionType>
<ns0:IPAddress>1.1.1.1</ns0:IPAddress>
<ns0:IsAllFaxesReceived>false</ns0:IsAllFaxesReceived>
<ns0:Contact>
<ns0:FirstName>Testzqdp</ns0:FirstName>
<ns0:LastName>Autozqdp</ns0:LastName>
<ns0:DateOfBirth>1964-02-25</ns0:DateOfBirth>
<ns0:SSN>15951</ns0:SSN>
<ns0:DriversLicenseNumber>HASDFASDF</ns0:DriversLicenseNumber>
<ns0:DriversLicenseState>TX</ns0:DriversLicenseState>
<ns0:IsActiveMilitary>false</ns0:IsActiveMilitary>
<ns0:EMailAddress>test449794@email.com</ns0:EMailAddress>
<ns0:EMailYears>0</ns0:EMailYears>
<ns0:EMailMonths>0</ns0:EMailMonths>
<ns0:HomePhone>9727253097</ns0:HomePhone>
<ns0:CellPho`enter code here`ne>973097</ns0:CellPhone>
</ns0:Contact>
在AngularJS中获取操作
var json = x2js.xml_str2json(data.XDocResponse[0]);
i / p参数包含xml，但json对象为null，我已遍历索引，xml的其他节点，但没有运气。 xml结构有什么问题吗？
请帮助我，因为我被困2天，非常感谢任何帮助