如何使用python匹配列表中包含单个句子的每个单词

Question

如何在python中匹配以下情况1 ..我希望句子中的每个单词都与列表匹配。

l1=['there is a list of contents available in the fields']
>>> 'there' in l1
False
>>> 'there is a list of contents available in the fields' in l1
True

Answer 1

简单方法

l1=['there is a list of contents available in the fields']
>>> 'there' in l1[0]
True

更好的方法是迭代到列表的所有元素。

l1=['there is a list of contents available in the fields']
print(bool([i for i in l1 if 'there' in i]))

Answer 2

如果您只是想知道列表中的任何字符串是否包含单词，无论它是哪个字符串，您都可以这样做：

if any('there' in element for element in li):
    pass

现在，如果您想过滤与字符串匹配的字符串，您可以简单地：

li = filter(lambda x: 'there' in x, li)

或者在Python 3中：

li = list(filter(lambda x: 'there' in x, li))