Question

我想从服务器获取一些数据并评估它如果我在json中评估1个元素，它工作正常，但如果我更多，我得到一个错误
这是操作（对ajax使用jquery）：

  ,getColsFromServer : function(){
    return [new Ext.grid.RowNumberer(),
          Ext.util.JSON.decode('{"id":"id","dataIndex":"id","header":"ID","width":"20","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}},{"dataIndex":"email","header":"Title","width":"120","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}}')//,{"id":"pixels","dataIndex":"pixels","header":"pixels","width":"120","sortable":"true","editor":{"xtype":"textarea","allowBlank":"false"}})
           ];
    }

如果你看看，我有2列id +电子邮件。使用2列返回错误： this.config [col]未定义
[中断此错误]返回this.config [col] .width;

使用一栏 - 工作正常。

这是上下文：我想建立自己的网格对象，所以这是用法：

var grid = new Ext.grid.GridPanel({
              loadMask: true,
            store: store,
            margins: '0 5 5 5',
            autoExpandColumn: 'id',
            plugins: [editor],

            tbar: minisites.getTopBar(editor,store,grid),

            bbar: minisites.getPagingBar(store , 1),

            columns: minisites.getCols()// THIS FUNCTION WILL RETURN THE OBJ FROM THE SERVER USING SYNCED AJAX REQUEST
        });

有什么想法吗？

Answer 1

如果要评估多个对象，则应将它们放在数组中。例如：

Ext.util.JSON.decode('[{"id":"id","dataIndex":"id","header":"ID","width":"20","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}},{"dataIndex":"email","header":"Title","width":"120","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}}]')

编辑：

如果你想返回一个哈希来通过一个名字访问每个项目（“id”和“email”，如果我做对了），你应该这样做：

Ext.util.JSON.decode('{ "id": {"id":"id","dataIndex":"id","header":"ID","width":"20","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}}, "email": {"dataIndex":"email","header":"Title","width":"120","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}}}')

编辑＃2：

在此上下文中，“getColsFromServer”应返回如下列的数组：

getColsFromServer : function(){
    return Ext.util.JSON.decode('[{"id":"id","dataIndex":"id","header":"ID","width":"20","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}},{"dataIndex":"email","header":"Title","width":"120","sortable":"true","editor":{"xtype":"textfield","allowBlank":"false"}}]');
    }

Answer 2

我怀疑您的列定义不正确。如果您为此更改代码，控制台中会显示什么？

var col = minisites.getCols();// THIS FUNCTION WILL RETURN THE OBJ FROM THE SERVER USING SYNCED AJAX REQUEST
console.dir(col);
var grid = new Ext.grid.GridPanel({
              loadMask: true,
            store: store,
            margins: '0 5 5 5',
            autoExpandColumn: 'id',
            plugins: [editor],

            tbar: minisites.getTopBar(editor,store,grid),

            bbar: minisites.getPagingBar(store , 1),

            columns: col
        });

EXTjs - Eval多json元素

2 个答案: