Question

如何从对象数组中删除项目？有一个属性数组，每个属性都需要删除与数组不重合的项目。这是一个例子：

let selectedIsn = [10,15,20,30,40];
let arayObject = [{
  isn:10,
  name:"Bolt"
}, {
  isn:13,
  name:"marry"
},{
  isn:15,
  name:"a"
},{
  isn:18,
  name:"q"
}, {
  isn:20,
  name:"marrys"
},{
  isn:25,
  name:"aa"
},{
  isn:30,
  name:"qa"
}, {
  isn:40,
  name:"marrya"
},{
  isn:55,
  name:"sa"
},{
  isn:68,
  name:"qas"
 }];

let deleteSelected = (q,selectedItems) => {
        let arrayNew = q,
            count=0;

    for (var m = 0; m < q.length; m++) {
        let index = selectedItems.indexOf(q[m]["isn"]);
        if (index > -1) {
            arrayNew.splice(m - count, 1);
            count++;
        }
    }
    return arrayNew;
}

deleteSelected(arayObject,selectedIsn);

不删除给定列表的所有元素。我不明白做错了什么。

Answer 1

您可以使用.filter函数从数组中获取所选项目

let deselected = arayObject.filter(function (a) {
   return selectedIsn.indexOf(a.isn) < 0;
});

Answer 2

只需使用像这样的过滤器

var result = arayObject.filter(item => selectedIsn.indexOf(item.isn)===-1);

如何从对象数组中删除项目？

2 个答案: