Question

我试图理解一个简单的Golang例程代码：

package main

import (
    "fmt"
    "time"
)

func sleep(seconds int, endSignal chan<- bool) {
    time.Sleep(time.Duration(seconds) * time.Second)
    endSignal <- true
}

func main() {
    endSignal := make(chan bool, 1)
    go sleep(3, endSignal)
    var end bool

    for !end {
        select {
        case end = <-endSignal:
            fmt.Println("The end!")
        case <-time.After(5 * time.Second):
            fmt.Println("There's no more time to this. Exiting!")
            end = true
        }
    }

}

那没关系，但为什么我不能在这个＆＃34;选择＆＃34;中使用简单的默认值。块？像这样：

for !end {
    select {
    case end = <-endSignal:
        fmt.Println("The end.")
    case <-time.After(4 * time.Second):
        fmt.Println("There's no more time to this. Exiting!")
        end = true
    default:
        fmt.Println("No end signal received.")
    }
}

获得此输出：

❯ go run goroutines-timeout.go
No end signal received!
No end signal received!
No end signal received!
No end signal received!
...
The end!

我无法理解为什么。

Answer 1

每次执行time.After(4 * time.Second)时，都会创建一个新的计时器频道。 select语句无法记住它在上一次迭代中选择的频道。您还采用了异步操作并将其转换为忙碌循环，从而违背了select语句的目的。

您需要的只是一个简单的选择，围绕您感兴趣的两个频道。它根本不需要循环。

select {
case <-endSignal:
    fmt.Println("The end!")
case <-time.After(4 * time.Second):
    fmt.Println("There's no more time to this. Exiting!")
}

https://play.golang.org/p/jb4EE8e6cw

如果你真的想要多次轮询，那么让定时器在for循环之外，这样每次迭代都会检查同一个

timeout := time.After(5 * time.Second)
pollInt := time.Second

for {
    select {
    case <-endSignal:
        fmt.Println("The end!")
        return
    case <-timeout:
        fmt.Println("There's no more time to this. Exiting!")
        return
    default:
        fmt.Println("still waiting")
    }
    time.Sleep(pollInt)
}

我怎样才能使用＆＃39; time.After＆＃39;和＆＃39;默认＆＃39;在Golang？

1 个答案: