curl -H "Accept: application/json" -H "Content-type: application/json" -X POST -d '{"firstname":"Mike","lastname":"Doel","customer_id":"12345","email":"test_api_user@gmail.com.com"}' -u API-key: APIURL(http://)
上面的语句运行良好的命令,但我无法通过下面的PHP代码实现相同的是我的代码
$url="https://apiurl";
$data=array("firstname"=>"Mike","lastname"=>"Doel","customer_id"=>"12345","email"=>"test_api_user@gmail.com");
$data_json=json_encode($data);
//Curl code
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json',"Accept: application/json","api-key"));
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS,$data_json);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$response = curl_exec($ch);
curl_close($ch);
答案 0 :(得分:0)
此:
mpg:cyl6
和
curl_setopt($ch, CURLOPT_HTTPHEADER, array([..snip..], "api-key"));
^^^^^
NOT 等效。 curl [..snip..] -u api-key
^^^^^^^^^^
使用-u
指定HTTP基本身份验证。您的setopt只是将该用户名填充为http标头的NAME,而不是基本身份验证凭据的显示方式
你应该
username:password
代替。
答案 1 :(得分:0)
In CURL, for api key you need to pass username:password , if you going to access in php code
$url="https://apiurl";
$curl = curl_init();
curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt_array($curl, array(
CURLOPT_URL => $url,
CURLOPT_HTTPAUTH => CURLAUTH_BASIC,
CURLOPT_USERPWD => 'username:password',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 300000,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => 'POST',
CURLOPT_HTTPHEADER => array(
"accept: application/json",
"content-type: application/json"
),
CURLOPT_POSTFIELDS => $postfields,
));
$response = curl_exec($curl);
$err = curl_error($curl);
curl_close($curl);
return $response;
尝试一次......希望这对你有用。