Question

假设我有一个数据集： ID NEXT ORDER 1456 1679 1 1679 1679 2 1578 1679 3 9492 1679 4

此数据集中唯一要更改的列是NEXT。 ID始终是唯一的，NEXT始终与单个ID相关联，并且将在每一行中重复。 ORDER是一个顺序的int。

我需要一个orderby或其他将执行以下排序的SQL语句：

NEXT ID始终位于订购的底部。

在NEXT的ORDER之后具有顺序更大ORDER的ID始终位于顶部

然后顺序从第二行开始顺序开始，ORDER是第一行的顺序之后的下一行

示例：

对于上表，订购将是 1578 9492 1456 1679

下一个已更改的另一个表：

ID NEXT ORDER 1456 1578 1 1679 1578 2 1578 1578 3 9492 1578 4

将是：

9492 1456 1679 1578

Answer 1

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[ViewController showAlertWithBackgroundColor:[UIColor greenColor] textColor:[UIColor whiteColor] message:message];}

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SQLFiddle
（小提琴使用Postgresql，因为Sql Server目前似乎已被打破）。

Answer 2

类似于Joel的回答，仅使用窗口函数而不是INNER JOIN或CROSS APPLY：

SELECT
    *
FROM
    #temp t
ORDER BY
    CASE
       WHEN t.[Order] > MAX(CASE WHEN ID = [NEXT] THEN [ORDER] END) OVER () THEN -999999999 + t.[Order]
       ELSE t.[Order]
    END

这是一个使用CROSS APPLY

的版本

SELECT
    t.*
FROM
    #temp t
    CROSS APPLY (SELECT [Order] FROM #temp WHERE ID = NEXT) n
ORDER BY
    CASE
       WHEN t.[Order] > n.[Order] THEN -99999999 + t.[Order]
       ELSE t.[Order]
    END

Answer 3

这应该有效：

示例数据：

IF OBJECT_ID('tempdb..#temp') IS NOT NULL
    DROP TABLE #temp;

CREATE TABLE #temp(ID      INT
              , [NEXT]  INT
              , [ORDER] INT);

INSERT INTO #temp
VALUES
      (1456
     , 1679
     , 1),
      (1679
     , 1679
     , 2),
      (1578
     , 1679
     , 3),
      (9492
     , 1679
     , 4);

QUERY：

DECLARE @rowcount INT;

SELECT @rowcount = COUNT(1)
FROM   #temp
WHERE  [ORDER] >
              (SELECT [ORDER]
               FROM   #temp
               WHERE  ID = [NEXT]);

SELECT ID
FROM
         (SELECT *
              , rn = ROW_NUMBER() OVER(ORDER BY [ORDER])
          FROM   #temp
          WHERE  [ORDER] >
                        (SELECT [ORDER]
                        FROM   #temp
                        WHERE  ID = [NEXT])
                        UNION
                        SELECT *
                            , rn = @rowcount + ROW_NUMBER() OVER(ORDER BY [ORDER])
                        FROM   #temp
                        WHERE  [ORDER] <=
                                      (SELECT [ORDER]
                                       FROM   #temp
                                       WHERE  ID = [NEXT])) AS A
ORDER BY rn;

结果：

根据轮换订购数据

3 个答案: