我有一个数组中的单词列表。我需要在字符串中查找任何这些单词的匹配项。
单词列表示例
company
executive
files
resource
示例字符串
Executives are running the company
这是我写的功能,但它不起作用
$matches = array();
$pattern = "/^(";
foreach( $word_list as $word )
{
$pattern .= preg_quote( $word ) . '|';
}
$pattern = substr( $pattern, 0, -1 ); // removes last |
$pattern .= ")/";
$num_found = preg_match_all( $pattern, $string, $matches );
echo $num_found;
输出
0
答案 0 :(得分:5)
$regex = '(' . implode('|', $words) . ')';
答案 1 :(得分:1)
<?php
$words_list = array('company', 'executive', 'files', 'resource');
$string = 'Executives are running the company';
foreach ($words_list as &$word) $word = preg_quote($word, '/');
$num_found = preg_match_all('/('.join('|', $words_list).')/i', $string, $matches);
echo $num_found; // 2
答案 2 :(得分:0)
请务必添加“m”标记,以使^
匹配一行的开头:
$expression = '/foo/m';
如果您不想匹配行的开头,请删除^