如果var express为true,我想在前3个可选日中添加一个类。
以下代码有效但如果我选择了一个日期,那么正在删除的类
$datepicker.datepicker({
dayNamesMin: ["S", "M", "D", "M", "D", "F", "S"],
beforeShowDay:$.datepicker.noWeekends,
firstDay: 1,
minDate: d,
dateFormat: "dd.mm.yy",
onSelect: function (dateText, inst) {
$('.delivery-date').text(dateText);
var printReleaseDateParts =dateText.split('.');
var printReleaseDate = new Date(printReleaseDateParts[2],printReleaseDateParts[1]-1,printReleaseDateParts[0]);
printReleaseDate.setDate(printReleaseDate.getDate() - printRelease);
$('.print-release-date').text($.datepicker.formatDate('dd.mm.yy', printReleaseDate));
$datepicker.removeClass('express');
if (express) {
$datepicker.addClass('express');
$('*[data-handler="selectDay"]:lt(3)').addClass('express');
} else {
$datepicker.removeClass('express');
$('*[data-handler="selectDay"]:lt(3)').removeClass('express');
}
},
onChangeMonthYear: function(){
console.log('onChangeMonthYear');
}
});
var express由复选框设置。最后,如果选中该复选框,则用户应该能够选择突出显示的快递日期。快递日期是常规首次选择日前3天。第一个可选日期由更改
上的复选框更改$('input:checkbox[name=option-express]').change(function () {
if ($(this).prop("checked") == true) {
$datepicker.addClass('express');
var d = calculateMinDate(deliveryExpress);
$datepicker.datepicker("option", "minDate", d);
$('*[data-handler="selectDay"]:lt(3)').addClass('express');
express = true;
} else {
$datepicker.removeClass('express');
var d = calculateMinDate(deliveryRegular);
$datepicker.datepicker("option", "minDate", d);
$('*[data-andler="selectDay"]:lt(3)').removeClass('express');
express = false;
}
});
应突出显示工作日。
那么突出头几天的最佳做法是什么?
修改
现在我为beforeShowDay实现了一个自定义函数,但没有运气。
表示,console.log被触发了四次,但是没有添加类。var expressDates = ["08/29/2016", "08/30/2016", "08/31/2016", "09/01/2016"];
function expressDays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0] && express) {
for (var i = 0; i < expressDates.length; i++) {
if (new Date(expressDates[i]).toString() == date.toString()) {
console.log('express day!')
return [true, 'express', 'Express'];
}
}
return [true, ''];
} else {
return noWeekend;
}
}
答案 0 :(得分:0)
function expressDays(date) {
var noWeekend = $.datepicker.noWeekends(date);
var expressDates = [];
for (var i = 0; i < deliveryExpress-1; i++) {
expressDates.push(moment($datepicker.datepicker("option", "minDate")).businessAdd(i).format('L'))
}
if (noWeekend[0] && express) {
var dateString = $.datepicker.formatDate('mm/dd/yy', date);
if($.inArray(dateString,expressDates) >=0){
return [true, 'express', 'Express'];
}else{
return [true, 'noexpress'];
}
} else {
return noWeekend;
}
}