我如何显示来自php的唯一数据，而循环结果不是由mysql查询？

Question

我有以下mysqli查询，该查询根据projects_log显示来自$cdid表的所有数据

$getlog = mysqli_query($link, "
    SELECT projects_log.*, users.username
    FROM projects_log 
    LEFT JOIN users ON users.user_id = projects_log.user_id
    WHERE projects_log.cdid = '$cdid'
    ORDER BY projects_log.pl_id DESC ");

此查询显示while循环中的以下数据

Project Name
=============
Mr. Bean
Mr. Benn
New Company3
New company project
Mobile
A T ETC
Mr. Bean
A Ten

现在从这个while循环结果，我首先显示最新的3个项目名称并隐藏所有剩余的“项目名称”。这个隐藏“项目名称”可以使用（+）按钮显示。像循环中显示/隐藏的东西：

$count = 4;
while ($fetclog = mysqli_fetch_array($getlog)) {
    $log_p_id = (int) $fetclog['p_id'];
    $log_username = inputvalid($fetclog['username']);
    $log_status = inputvalid($fetclog['status']);
    $new_log_status = inputvalid($fetclog['status']);
    $log_date = inputvalid($fetclog['date_time']);
    $expand = explode(':', $log_date);
    $log_date = $expand[0] . $expand[1];
    $getproject_name = mysqli_query($link, "SELECT projects.p_name, company.* FROM projects LEFT JOIN company ON projects.cid = company.cid WHERE p_id = '$log_p_id'  ");
    $log_result = mysqli_fetch_array($getproject_name);
    $log_projectName = $log_result['p_name'];
    $log_company = $log_result['company_name'];
    $get_name = mysqli_query($link, "SELECT status_name FROM status WHERE sid = '$new_log_status' ");
    $get_result = mysqli_fetch_array($get_name);
    $new_log_status = $get_result['status_name'];
    if (empty($new_log_status)) {
        $new_log_status = "Long List";
    } else {
        $new_log_status = $new_log_status;
    }

    // if logged in user is a owner of this project or having any assign project...
    $logged_user_id = $_SESSION['user_id'];
    $project_check = mysqli_query($link, "SELECT p_id FROM projects WHERE p_owner_id = '$logged_user_id' ");
    $project_check_2 = mysqli_query($link, "SELECT p_id FROM projects_assign_users WHERE assign_user_id = '$logged_user_id' ");
    $exit_p_id = array();
    while ($project_check_fetch = mysqli_fetch_array($project_check)) {
        $exit_p_id[] = $project_check_fetch['p_id'];
    }
    $exit_p_id_2 = array();
    while ($project_check_fetch_2 = mysqli_fetch_array($project_check_2)) {
        $exit_p_id_2[] = $project_check_fetch_2['p_id'];
    }

    if ($count > $count_num) {

        echo "<tr class='collapse_project_log'>";
        if (in_array($log_p_id, $exit_p_id) || in_array($log_p_id, $exit_p_id_2)) {
            echo "<td valign='top'><a class='project' onclick='getProjectForm($log_p_id)'>$log_projectName</a></td>";
        } else {
            echo "<td valign='top'>$log_projectName</td>";
        }
        // if logged in user is a owner of this project or having any assign project...d    
        echo "<td valign='top'>$log_company</td>";
        echo "<td valign='top'>$log_username</td>";
        echo "<td valign='top'><a><label class='' for='modal-2' onclick='showpstatus($cdid, $log_p_id);'>$new_log_status</a></label></td>";
        echo "<td valign='top'>$log_date</td>";
        echo "</tr>";
    } else {
        echo "<tr>";
        if (in_array($log_p_id, $exit_p_id) || in_array($log_p_id, $exit_p_id_2)) {
            echo "<td valign='top'><a class='project' onclick='getProjectForm($log_p_id)'>$log_projectName</a></td>";
        } else {
            echo "<td valign='top'>$log_projectName</td>";
        }
        echo "<td valign='top'>$log_company</td>";
        echo "<td valign='top'>$log_username</td>";
        echo "<td valign='top'><a><label class='' for='modal-2' onclick='showpstatus($cdid, $log_p_id);'>$new_log_status</a></label></td>";
        echo "<td valign='top'>$log_date</td>";
        echo "</tr>";
    }
    $count++;
}

以上所有工作正常。

现在，在3个可见的最新项目中，它向我展示：

Project Name
============
Mr. Bean
Mr. Bean
New Company

但我希望这个前3个可见项目的名称应该是唯一的。我怎么能这样做？

类似于显示来自while循环的唯一数据结果不使用mysql查询。