Question

我将所有sql存储在另一个文件中调用db_function.php 这是代码

<?php
class DB_Functions
{
    private $conn;

    function __construct()
    {
        require_once'conn.php';
        $conn = mysqli_connect("localhost","root","","phpstmt");
    }

    function __desturct() 
    {
    }

    public function add($tablename,$colname,$dataname)
    {
        $sql = "INSERT INTO ".$tablename." (".$colname.") VALUES (".$dataname.")";
        $result= mysqli_query(mysqli_connect("localhost","root","","phpstmt"), $sql);
        return $result;
    }
}
?>

这里是index.php中的我的代码，其中是接口

if(isset($_POST['btnsubmit'])) {
    $dataphp = $_POST["data"];
    $datatwophp = $_POST["datatwo"];
    $colname = "data,datatwo";
    $dataname = "'$dataphp','$datatwophp'";
    $result = $db->add($tablename,$colname,$dataname);
    //$sql = "INSERT INTO `table` (`data`,`datatwo`) VALUES ('$dataphp','$datatwophp')";
    if($result) {
        echo "success";
    } else {
        echo "WrongE: " . $result . "<br>" . mysqli_error($conn);
    }
}

我甚至不知道错误是什么，因为错误输出只是一个WrongE，$结果就像消失一样。

欣赏并回答。

Answer 1

排队

echo "WrongE: " . $result . "<br>" . mysqli_error($conn);

您无法访问DB_Functions属性$conn。如果您愿意，可以在DB_Functions类

中添加一种方法

public function getConn()
{
    return $this->conn;
}

然后你必须从构造函数

替换这一行

$conn = mysqli_connect("localhost","root","","phpstmt");

用这个

$this->conn = mysqli_connect("localhost","root","","phpstmt");

然后你需要替换这行代码

echo "WrongE: " . $result . "<br>" . mysqli_error($conn);

用这个

echo "WrongE: " . $result . "<br>" . mysqli_error($db->getConn());

或者如果你想要，你可以在DB_Functions类中添加一个特殊方法来获取错误

public function getError()
{
    return mysqli_error($this->conn);
}

然后就可以像这样使用这种方法

echo "WrongE: " . $result . "<br>" . $db->getError();

$result并未消失 - 当您尝试将其作为字符串回显时，不会显示false值。如果你试试这个代码

$test = false;
$string = ':' . $test . ':';
echo $string;

然后你会看到输出上的::字符串。

你的最后一堂课看起来像这样

<?php
class DB_Functions
{
    private $conn;

    function __construct()
    {
        require_once'conn.php';
        $this->conn = mysqli_connect("localhost","root","","phpstmt");
    }

    function __desturct() 
    {
    }

    public function add($tablename,$colname,$dataname)
    {
        $sql = "INSERT INTO ".$tablename." (".$colname.") VALUES (".$dataname.")";
        $result= mysqli_query(mysqli_connect("localhost","root","","phpstmt"), $sql);
        return $result;
    }

    public function getError()
    {
        return mysqli_error($this->conn);
    }
}
?>

然后你的index.php看起来像这样

if(isset($_POST['btnsubmit'])) {
    $dataphp = $_POST["data"];
    $datatwophp = $_POST["datatwo"];
    $colname = "data,datatwo";
    $dataname = "'$dataphp','$datatwophp'";
    $result = $db->add($tablename,$colname,$dataname);
    //$sql = "INSERT INTO `table` (`data`,`datatwo`) VALUES ('$dataphp','$datatwophp')";
    if($result) {
        echo "success";
    } else {
        echo "WrongE: " . $result . "<br>" . $db->getError();
    }
}

当我尝试使php更多OOP时插入错误

1 个答案: