Question

我的问题是如何询问用户他/她是否想再次输入。恩。你想再计算一下吗？是或否。

有人可以解释我做错了什么并修正错误。

int main() {
}
int a;
cout << endl << "Write 1 for addition and 0 for substraction:" << endl;
cin >> a;

// addition
if (a == 1) {
    cout << "You are now about to add two number together, ";
    cout << "enter a number: " << endl;
    int b;
    cin >> b;
    cout << "one more: " << endl;
    int c;
    cin >> c;
    cout << b + c;
}
//Substraction
else if (a == 0) {
    cout << "enter a number: " << endl;
    int b;
    cin >> b;
    cout << "one more: " << endl;
    int c;
    cin >> c;
    cout << b - c;
}
//If not 1 or 0 was called
else {
    cout << "Text" << endl;

}
    return 0;
}

Answer 1

int main()
{
    string calculateagain = "yes";
    do
    { 
        //... Your Code
        cout << "Do you want to calculate again? (yes/no) "
        cin >> calculateagain;
    } while(calculateagain != "no");
    return 0;
}

需要注意的重要事项：

未选中此选项，因此用户输入可能无效，但循环将再次运行。
您需要包含<string>才能使用字符串。

简化的计算代码

int a;
cout << endl << "Write 1 for addition and 0 for substraction:" << endl;
cin >> a;
cout << "enter a number: " << endl;
int b;
cin >> b;
cout << "one more: " << endl;
int c;
cin >> c;
// addition
if (a == 1) {
    cout << b + c;
}
//Substraction
else if (a == 0) {
    cout << b - c;
}
//If not 1 or 0 was called
else {
    cout << "Invalid number!\n";
    continue; //restart the loop

}

此代码应位于do ... while循环内。

如何再次请求输入c ++

1 个答案: