Question

我正在测试一个小的C＃程序片段：

        short min_short = (short)(int)-Math.Pow(2,15);   
        short max_short = (short)(int)(Math.Pow(2, 15) - 1);
        Console.WriteLine("The min of short is:{0};\tThe max of short is:{1}", min_short, max_short);

        int min_int = (int)-Math.Pow(2, 31);
        int max_int = (int)(Math.Pow(2, 31) - 1);
        Console.WriteLine("The min of int is:{0};\tThe max of int is:{1}", min_int, max_int);

        uint min_uint = 0;
        uint max_uint = (uint)(Math.Pow(2, 32) - 1);
        Console.WriteLine("The min of uint is:{0};\tThe max of uint is:{1}", min_uint, max_uint);

        long min_long = (long)-Math.Pow(2, 63);
        long max_long = (long)(Math.Pow(2, 63) - 1);
        Console.WriteLine("The min of long is:{0};\tThe max of long is:{1}", min_long, max_long);

        ulong min_ulong = 0;
        ulong max_ulong = (ulong)(Math.Pow(2, 64) - 1);
        Console.WriteLine("The min of ulong is:{0};\tThe max of ulong is:{1}", min_ulong, max_ulong);

输出结果为：

The min of ushort is:0; The max of ushort is:65535
The min of short is:-32768;     The max of short is:32767
The min of int is:-2147483648;  The max of int is:2147483647
The min of uint is:0;   The max of uint is:4294967295
The min of long is:-9223372036854775808;The max of long is:-9223372036854775808
The min of ulong is:0;  The max of ulong is:0

我怀疑这个错误是由Math.Pow（）的函数引起的，这是返回的双重类型。

public static double Pow(
    double x,
    double y
)

所以，我的问题是：长型是否有类似的数学函数？如何纠正上面程序片段中的错误。非常感谢！

Answer 1

您达到Math.Pow限制。您需要使用System.Numerics.BigInteger.Pow。

Answer 2

    public static ulong Power(ulong A, ulong n)
    {
        ulong result = n;
        for(ulong i = 0; i < A; i++)
        {
            result *= A;
        }
        return result;
    }

    static void Sample()
    {
        Console.WriteLine("Result: " + Power(12, 62));
    }

输出结果：552798227791872

Answer 3

  public static long Power(long A, ulong n)
    {
        long result = 1;    // if n==0,A^n==1

        if (n>0)
        {
            do
            {
                result *= A;
                n--;
            } while (n>0);
        }            
        return result;
    }

对于长型是否有Math.Pow（A，n）函数？

3 个答案: