我有这个脚本工作正常,允许用户投票,但我是如何做出投票按钮的东西,再次点击它切换回正常图像!就像stackoverflow:
这是我的剧本:
$(document).ready(function() {
$('.statuses').delegate('.vote_up', 'click', function(e) {
//stop event
e.preventDefault();
//get the id
var the_id = $(this).closest('.message').attr('id').split('_').pop();
//the main ajax request
$.ajax({
context: this,
type: "POST",
// Make sure "this" in the callback refers to the element clicked
data: "action=vote_up&id=" + the_id,
url: "ajax/votes.php",
success: function (msg) {
$(this).siblings("span.vote_count").html(msg).fadeIn();
// get the child <img> and set its src
$(this).children("img").attr("src", "img/uparrowActive.png");
}
});
});
HTML:
<ul class="statuses">
<li id="set_41" class="message">
<span class="vote_count">0</span>
<a href="#" class="vote_up"><img src="img/uparrow.png" /></a>
这是我想要发生的伪语言:
a user clicks vote image, it changes the image(uparrowActive)
//I've done that already
then
if user clicks the same image again it goes back to normal image(uparrow)
答案 0 :(得分:0)
jquery has a toggle event,允许您将两个事件处理程序绑定到一个交替调用的元素。
*未经测试,可能有简单的语法错误。
myElement.toggle(vote(), unvote());
function vote()
{
// add a vote to the item
// change icon to vote icon
}
function unvote()
{
// remove a vote from the item
// change icon to default icon.
}