快速按钮按复制文本

Question

我在集合视图中的单元格内有一个按钮，除了我尝试创建的复制功能外，一切正常。当我单击按钮时，不会复制文本，或者在我的测试用例中，文本不会打印到控制台。

    cell.buttonViewLink.addTarget(self, action: "buttonViewLinkAction:", forControlEvents: UIControlEvents.TouchUpInside)

    func buttonViewLinkAction(sender:UIButton!) {
        print("Button tapped")

    }

在我的故事板中，我有一个从按钮链接到视图的内部动作（我用ctrl-drag形式创建了这个按钮来查看）。一切看起来还不错，但是当我按下按钮时没有任何反应，当事情看起来没问题时也不会崩溃。

我错过了什么？

Answer 1

喜欢

复制

 func buttonViewLinkAction(sender:UIButton!) {
        print("Button tapped")
       UIPasteboard.generalPasteboard().string = yourstring!.text() // or use  sender.titleLabel.text

    }

粘贴或检索

func GetCopiedText(sender: UIButton!) {

    if let myString = UIPasteboard.generalPasteboard().string {
        print(myString)
    }

}

<强>更新

 func buttonViewLinkAction(sender:UIButton!) {
        print(sender.currentTitle)
         print(sender.titleLabel.text)
 }

<强>更新-2

您将buttonViewLinkAction代码写入其永不调用的func collectionView(collectionView: UICollectionView, cellForItemAtIndexPath indexPath: NSIndexPath)内。所以删除buttonViewLinkAction并在数据源方法之外添加

 //fontawesome link
    cell.buttonViewLink.setTitle(String.fontAwesomeIconWithName(.Link), forState: .Normal)
    cell.buttonViewLink.titleLabel?.font = UIFont.fontAwesomeOfSize(20)
    cell.buttonViewLink.addTarget(self, action: "buttonViewLinkAction:", forControlEvents: UIControlEvents.TouchUpInside)

    func buttonViewLinkAction(sender:UIButton!) {
        print("Button tapped")
        UIPasteboard.generalPasteboard().string = "Label text"

    }

最终答案

 func collectionView(collectionView: UICollectionView, cellForItemAtIndexPath indexPath: NSIndexPath) -> UICollectionViewCell {
    let cell = collectionView.dequeueReusableCellWithReuseIdentifier("cell", forIndexPath: indexPath) as! CellClass
    let face = self.faces[indexPath.item]

    //set image and align center
    if let imageURL = NSURL(string:face.image) {
        cell.imageView.sd_setImageWithURL(imageURL)

    } else {
        cell.imageView.image = self.placeholderImage
    }

    //set name
    if let imageNAME: String = String(face.name){
        cell.labelView.text = (imageNAME .uppercaseString)

    } else {
        cell.labelView.text = "oops name"
    }

    //set border
    cell.layer.shadowOffset = CGSizeMake(0, 1)
    cell.layer.shadowColor = UIColor.blackColor().CGColor
    cell.layer.shadowRadius = 1
    cell.layer.shadowOpacity = 0.1
    cell.clipsToBounds = false
    let shadowFrame: CGRect = (cell.layer.bounds)
    let shadowPath: CGPathRef = UIBezierPath(rect: shadowFrame).CGPath
    cell.layer.shadowPath = shadowPath

    //square background button
    cell.buttonViewSquare.backgroundColor = UIColor(red: 249/255, green: 249/255, blue: 249/255, alpha: 1)
    cell.buttonViewSquare.enabled = false

    //fontawesome link
    cell.buttonViewLink.setTitle(String.fontAwesomeIconWithName(.Link), forState: .Normal)
    cell.buttonViewLink.titleLabel?.font = UIFont.fontAwesomeOfSize(20)
    cell.buttonViewLink.addTarget(self, action: "buttonViewLink:", forControlEvents: UIControlEvents.TouchUpInside)
    // or use like    cell.buttonViewLink.addTarget(self, action: "buttonViewLinkAction:", forControlEvents: UIControlEvents.TouchUpInside)




    //fontawesome heart
    cell.buttonViewHeart.setTitle(String.fontAwesomeIconWithName(.Heart), forState: .Normal)
    cell.buttonViewHeart.titleLabel?.font = UIFont.fontAwesomeOfSize(20)
    cell.buttonViewHeart.setTitleColor(UIColor.redColor(), forState: UIControlState.Normal)

    //fontawesome share
    cell.buttonViewShare.setTitle(String.fontAwesomeIconWithName(.Share), forState: .Normal)
    cell.buttonViewShare.titleLabel?.font = UIFont.fontAwesomeOfSize(20)




    return cell
}

调用方法如

  func buttonViewLink(sender:UIButton!) {
        print("Button tapped")
        UIPasteboard.generalPasteboard().string = sender.titleLabel.text

    }

或直接使用你已经有了一个功能

  @IBAction func buttonViewLinkAction(sender: UIButton) {
         print("Button tapped")
        UIPasteboard.generalPasteboard().string = sender.titleLabel.text
  }

修改后的答案

在此处添加标记cell.buttonViewLink.tag = indexPath.item

     cell.buttonViewLink.setTitle(String.fontAwesomeIconWithName(.Link), forState: .Normal)
    cell.buttonViewLink.titleLabel?.font = UIFont.fontAwesomeOfSize(20)
    cell.buttonViewLink.addTarget(self, action: "buttonViewLinkAction:", forControlEvents: UIControlEvents.TouchUpInside)
         cell.buttonViewLink.tag = indexPath.item

并调用类似

的方法

@IBAction func buttonViewLinkAction(sender: UIButton) {
         print("Button tapped")
        let face = self.faces[sender.tag]
         if let imageNAME: String = String(face.name){
           print(imageNAME .uppercaseString)
           }
           if let imageURL = NSURL(string:face.image) {
            print(imageURL)

           }
        UIPasteboard.generalPasteboard().string = sender.titleLabel.text
  }

Answer 2

您刚刚发布了代码。问题是你在内部功能。请把它拿出来，它运作良好。

为什么你不这样使用它：

cell.buttonViewLink.setTitle(String.fontAwesomeIconWithName(.Link), forState: .Normal)
cell.buttonViewLink.titleLabel?.font = UIFont.fontAwesomeOfSize(20)
cell.buttonViewLink.addTarget(self, action: "buttonViewLinkAction:", forControlEvents: UIControlEvents.TouchUpInside)

func buttonViewLinkAction(sender:UIButton!) {
    print("Button tapped")
    UIPasteboard.generalPasteboard().string = "Label text"

}

Answer 3

你有两个重复的buttonViewLinkAction功能！ 按下按钮时，将调用此功能：

@IBAction func buttonViewLinkAction(sender: UIButton) {
}

而不是

func buttonViewLinkAction(sender:UIButton!) {
    print("Button tapped")
}

删除第二个函数并在第一个函数中编写代码。

此外，您不需要写这一行：

cell.buttonViewLink.addTarget(self, action: "buttonViewLinkAction:", forControlEvents: UIControlEvents.TouchUpInside)

如果您已将按钮链接到该功能（在故事板中）。

Answer 4

更新Swift 4.2

override func viewDidLoad() {
    super.viewDidLoad()
    label.addGestureRecognizer(UILongPressGestureRecognizer(target: self, action: #selector(copyValuePressed)))
}

@objc func copyValuePressed() {
    UIPasteboard.general.string = label.text
}