如何选择帖子的最后编辑版本?

时间:2016-08-27 05:21:49

标签: mysql sql database select

我有一个像SO这样的问答网站。我还有一个表格,其中包含问题和答案及其编辑版本。这是我的表结构:

// QandA
+----+---------+---------------------------+---------+------+-----------+
| id |  title  |            body           | related | type | edited_id |
+----+---------+---------------------------+---------+------+-----------+
| 1  | title1  | question content          | NULL    | 0    | NULL      |
| 2  |         | answer content            | 1       | 1    | NULL      | 
| 3  | title2  | question content          | NULL    | 0    | NULL      |
| 4  |         | answer content            | 3       | 1    | NULL      |
| 5  |         | answer content            | 1       | 1    | NULL      |
| 6  |         | answer content (edited)   | NULL    | 1    | 2         |
| 7  | title3  | question content          | NULL    | 0    | NULL      |
| 8  | title1  | question content (edited) | NULL    | 0    | 1         |
| 9  |         | answer content            | 7       | 1    | NULL      |
| 10 | title1  | question content (edited) | NULL    | 0    | 1         |
| 11 | title3  | question content (edited) | NULL    | 0    | 7         |
+----+---------+---------------------------+---------+------+-----------+

专栏解释:

related列:

  • NULL用于问题和问题/答案的编辑版本
  • {the id of its own question}获取答案

type列:

  • 0提问
  • 1获取答案

edited_id列: (原始帖子的ID)

  • NULL表示这是原始问题/答案
  • {any number}表示它是问题/答案的编辑版本。

现在我需要一个查询来选择一个问题及其所有答案。注意到我需要选择最后编辑的版本(如果已经编辑过)

示例1:我有这个值::id = 1我想要这个输出:

+----+---------+---------------------------+---------+------+-----------+
| id |  title  |            body           | related | type | edited_id |
+----+---------+---------------------------+---------+------+-----------+
| 10 | title1  | question content (edited) | NULL    | 0    | 1         |
| 6  |         | answer content (edited)   | NULL    | 1    | 2         |
| 5  |         | answer content            | 1       | 1    | NULL      |
+----+---------+---------------------------+---------+------+-----------+

示例2:我有这个值::id = 3我想要这个输出:

+----+---------+---------------------------+---------+------+-----------+
| id |  title  |            body           | related | type | edited_id |
+----+---------+---------------------------+---------+------+-----------+
| 3  | title2  | question content          | NULL    | 0    | NULL      |
| 4  |         | answer content            | 3       | 1    | NULL      |
+----+---------+---------------------------+---------+------+-----------+

示例2:我有这个值::id = 7我想要这个输出:

// QandA
+----+---------+---------------------------+---------+------+-----------+
| id |  title  |            body           | related | type | edited_id |
+----+---------+---------------------------+---------+------+-----------+
| 11 | title3  | question content (edited) | NULL    | 0    | 7         |
| 9  |         | answer content            | 7       | 1    | NULL      |
+----+---------+---------------------------+---------+------+-----------+

这是我当前的查询:

SELECT *
FROM QandA
WHERE (id = :id AND type = 0) OR
      (related = :id AND type = 1)
ORDER BY type -- noted that the order of answers doesn't matter

如您所见,我的查询不支持已编辑的版本。无论如何,如果该帖子的编辑行有什么替换编辑后的帖子版本?

注意:请不要告诉我“不要将问题和答案放在同一张桌子上”,因为我知道。但现在我需要解决上面的问题。

1 个答案:

答案 0 :(得分:1)

您可以尝试以下查询:

SET @qid := 1;

SELECT 
QA.*
FROM QA 
INNER JOIN 
(
    SELECT 
    MAX(GREATEST(A.id, COALESCE(B.id, 0))) latest_id
    FROM QA A 
    LEFT JOIN QA B ON A.id = B.edited_id 
    WHERE @qid IN(A.id,A.related,A.edited_id)
    GROUP  BY A.type , IF(A.type = 1, A.id,0)
) AS t 
ON QA.id = t.latest_id

WORKING DEMO