Question

我正在尝试对Object进行简单的JSON字符串转换。这是代码：

let u = "somehost.com/api/1/ipa/2"
let url = NSURL(string: u )!

let data = NSData(contentsOfURL: url)!

let parsed: AnyObject? = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.AllowFragments) 

if let json = parsed as? [String: AnyObject]{
    // never enters this if statement.
}

但它不能正确解开。在我看来，这应该简单得多。有人可以帮忙吗？还使用＆＃34; Xcode 7.3和swift 2.2＆＃34;。

我想避免使用第三方库。

Answer 1

示例Json Parsing Fetch和read这样简单易懂的理解过程。点击下面的链接，你会看到响应为字典，在字典里面有一个数组.......

   let WebURL = "http://api.randomuser.me/"

    let url2 = NSURL(string:WebURL)

    let data = NSData(contentsOfURL: url2!)

    do
    {

       let dictionary = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments) as! NSMutableDictionary

        print(dictionary)

        let arrayOfValues = dictionary .objectForKey("results") as! NSMutableArray

        print(arrayOfValues)


        for var i = 0; i<arrayOfValues.count; i++ {


            let resultDictInsideArray = arrayOfValues.objectAtIndex(i)

            let NameDict = resultDictInsideArray.objectForKey("name")!

            let locDict = resultDictInsideArray.objectForKey("location")!



            print(NameDict.objectForKey("title")!)
            print(locDict.objectForKey("street")!)



        }


    }catch {

    print("error")


    }

如果您的网址有空格，请像这样编写网址代码

 let url = NSURL(string: stringUrl.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!)!

Answer 2

您确定返回的内容不是数组而不是对象吗？

你试过这个：

if let json = parsed as? [AnyObject]{
}

Answer 3

       func getDataFromServer(myGetUrl : URL) {
        let url = myGetUrl
        //create the session object
        let session = URLSession.shared

        //now create the URLRequest object using the url object
        let request = URLRequest(url: url )

        //create dataTask using the session object to send data to the server
        let task = session.dataTask(with: request as URLRequest, completionHandler: { data, response, error in

            guard error == nil else {
                print(error as Any)
                return
            }

            guard let data = data else {
                return
            }

            do {
                //create json object from data
                if let json = try JSONSerialization.jsonObject(with: data, options: []) as? [[String:AnyObject]] {
                    //print(json)
                    self.getResponsedata = json
                    //print("Here: \(self.getResponsedata)")
                    self.getDelegate.GetdataReceivedFromServer(data: self.getResponsedata , url : myGetUrl)
                }
            } catch let error {
                print(error.localizedDescription)
            }
        })
        task.resume()
    }
}

如何在Swift中将JSON解析为[String：AnyObject]

3 个答案: