Django CustomField继承自models.CharField - 意外的关键字参数

时间:2016-08-26 21:36:06

标签: python django postgresql django-models

我的应用程序需要几个字段所需的属性,所以我去了并遵循代码来创建custom fields

这是我的CustomCharacterField:

class CustomCharField(models.CharField):
    def __int__(self, success_order=None, *args, **kwargs):
        self.success_order = success_order
        super(CustomCharField, self).__int__( *args, **kwargs)

    def get_success_order(self):
        return int(self.success_order)


    def deconstruct(self):
        name, path, args, kwargs = super(CustomCharField, self).deconstruct()
        del kwargs["success_order"]
        return name, path, args, kwargs

这是我的models.py

class NameModel(models.Model):

     name = fields.CustomCharField(max_length=250, unique=True, success_order=1)

这是追溯:

 File "/home/kt/Documents/phc/phc/Forms/models.py", line 204, in <module>
   class SchemeModel(models.Model):
  File "/home/kt/Documents/phc/phc/Forms/models.py", line 220, in SchemeModel
    scheme_name = fields.CustomCharField(verbose_name="Scheme", max_length=250, unique=True, success_order=1)
  File "/usr/local/lib/python3.4/dist-packages/django/db/models/fields/__init__.py", line 1072, in __init__
    super(CharField, self).__init__(*args, **kwargs)
TypeError: __init__() got an unexpected keyword argument 'success_order'

2 个答案:

答案 0 :(得分:3)

我认为你这里只有一个拼写错误 - def __int__应该是def __init__super(...).__int__(..)来电应该是super(...).__init__(..)

答案 1 :(得分:-1)

这是因为您传递参数的顺序。回溯显示success_order正被传递给CharField的构造函数,而不应该这样。这是因为它是以kwargs传递的。改变顺序应该可以解决问题。 unique = True将被CharField构造函数接受。