Question

在python中，使用最快的方式将scheme://netloc/path;parameters?query#fragment类型的网址转换为＆＃34;方案相对＆＃34;或＆＃34;协议相对＆＃34; URI？

目前，我正在使用this的版本，但我认为可能有更简洁/更快的方式来完成此任务。输入始终附加https://或http://。

Answer 1

我能找到的最快的方法是str.partition：

In [1]: url = 'https://netloc/path;parameters?query#fragment'

In [2]: %timeit url.partition('://')[2]
The slowest run took 6.70 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 251 ns per loop

In [3]: %timeit url.split('://', 1)[1]
The slowest run took 5.20 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 407 ns per loop

In [4]: %timeit url.replace('http', '', 1).replace('s://', '', 1)
The slowest run took 4.24 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 589 ns per loop

由于您所做的只是剥离以固定字符串结尾的文本，因此解析URL似乎没什么好处。

Answer 2

from urlparse import urlparse
o = urlparse('http://www.cwi.nl:80/%7Eguido/Python.html')

print o.scheme
print o.netloc
print o.path

我可能会这样做......

将URI转换为方案相对URI的最快方法（在python中）

2 个答案: