Question

我无法理解这一点。该程序没有问题。问题在于，无论用户输入是什么，if语句都会继续，并且程序不会检查else if语句。我假设我的脚本中存在更大的结构问题，但我不确定它是什么。

这可能是find函数的问题。我还不熟悉这个功能。

这也可能与我如何在另一个if语句中嵌套这个新的if-else-if语句有关。

问题出现在代码的最后，在最后的if-else-if中。我正在粘贴整个事情，以防它在代码中的其他地方出现更深层次的问题。之前的if语句运行正常。这是具有问题的具体代码：

if (song.find(str2)){
        cout << "Thank you! I, personally, love this song.\n";
        cout << "I probably wouldn't listen to you if you asked me to turn it off.\n";
        Sleep(20000);
    }
    else if (song.find(str3)){
        cout << "It's not coming off, " << name <<"." << endl;
    }

感谢您的帮助。非常感谢：）

这是完整的代码：

#include <iostream>
#include <windows.h>
#include <string>

using namespace std;

int emotion;


void Sleep()
{
    Sleep();
}

void loneliness()
{
    cout << "Lonely. You must be strong, and loved, if you choose this feeling to explore.";
}

void inlove()
{
    cout << "In love. You've been watching telenovelas again.";
}

void ambitious()
{
    cout << "Ambitious. Steve Jobs Steve Jobs.";
}

void happy()
{
    cout << "Happy. Is this a thing you can just feel?";
}

int main() {

    string input;
    string input2;
    string name;

cout << "I'm bad." << endl;
cout << "My name's Raab." << endl;
cout << "Your name?" << endl;
getline(cin, name);
cout << "Tell me in one word what emotion you're feeling right now." << endl;
getline(cin, input);
cout << "Haha. " << input << "?" << " " << "Alright. I can work with that." << endl;

cout << "..." << endl;
cout << "Okay, I'm going to give you a choice." << endl;
cout << "You can trade that emotion for one other, if you'd like." << endl;
cout << "Would you like to do that?" << endl;
getline(cin, input2);

if (input2 == "Yes" && "yes") {

    int emotion;

    cout << "Nice one, bro.\n";
    Sleep(350);
    cout << "Here are your options!\n";
    Sleep(300);
    cout << "1. Lonely\n";
    cout << "2. In love.\n";
    cout << "3. Ambitious.\n";
    cout << "4. Happy.\n";
    cin >> emotion;

switch (emotion) {
case 1:
    loneliness();
    break;
case 2:
    inlove();
    break;
case 3:
    ambitious();
    break;
case 4:
    happy();
    break;
}
cin.get();


}

else if (input2 == "No" && "no")
{

    std::string song;
    std::string str2 ("like");
    std::string str3 ("off");

    cout << "Well" << endl;
    Sleep(250);
    PlaySound(TEXT("whip"), NULL, SND_ASYNC|SND_FILENAME);
    cout << "." << endl;
    Sleep(300);
    PlaySound(TEXT("whip"), NULL, SND_ASYNC|SND_FILENAME);
    cout << "." << endl;
    Sleep(300);
    PlaySound(TEXT("whip"), NULL, SND_ASYNC|SND_FILENAME);
    cout << "." << endl;
    Sleep(300);
    PlaySound(TEXT("gravity"), NULL, SND_ASYNC|SND_FILENAME);
    Sleep(2500);
    cout << "Here we go. You like this song? Or do you want me to turn it off?\n";
    Sleep(2000);
    cout <<"Wait.\n";
    Sleep(2000);
    cout << "Don't tell me yet. I'm grooving.\n";
    Sleep(7000);
    cout << "Okay, tell me what to do, " << name << "." << endl;
    getline(cin, song);

    if (song.find(str2)){
        cout << "Thank you! I, personally, love this song.\n";
        cout << "I probably wouldn't listen to you if you asked me to turn it off.\n";
        Sleep(20000);
    }
    else if (song.find(str3)){
        cout << "It's not coming off, " << name <<"." << endl;
    }

    return 0;
    }

return 0;
}

**编辑：

我解决了这个问题。

我将上面的代码提取改为：

if (~song.find(str2))
    {
        cout << "Thank you! I, personally, love this song.\n";
        cout << "I probably wouldn't listen to you if you asked me to turn it off.\n";
        Sleep(20000);
    }
    else if (!~song.find(str2))
    {
        cout << "It's not coming off, " << name <<"." << endl;
        Sleep(20000);
    }

因此它不再检查str3，但确实检查str2是否不存在。这是进步，并捏造一个解决方案，但它并没有真正让我更深刻的理解，我可以提出我，所以我仍然会欣赏答案:) **

Answer 1

该行不正确：

if (input2 == "Yes" && "yes")

&&并没有这样做。您必须与if语句中的每个值执行比较。它应该是：

if(input2 == "Yes" || input2 =="yes")

同样，该行

else if (input2 == "No" && "no")

应该是：

if(input2 == "No" || input2 =="no")

C ++如果，否则如果没有读取其他的话。或查找功能不正确？

1 个答案: