Question

我想用这部分代码创建一个高级搜索功能

 //search.php?name= &country= &city= &age= &gender=
$search_name = 0;
$search_country = 0;
$search_city = 0;
$search_age = 0;
$search_gender = 0;
$allow_querry = false;

if((isset($_GET["name"])) AND ($_GET["name"] != "")) {
 $name = $_GET["name"];
 $search_name = 1;
  }

 if((isset($_GET["country"])) AND ($_GET["country"] != "")) {
 $country = $_GET["country"];
$search_country = 1;
 }

 if((isset($_GET["city"])) AND ($_GET["city"] != "")) {
 $city = $_GET["city"];
 $search_city = 1;
  }

  if((isset($_GET["age"])) AND ($_GET["age"] != "")) {
  $age = $_GET["age"];
   $search_age = 1;

  $age = date('Y', strtotime('-'.$age.' years'));
  }

  if((isset($_GET["gender"])) AND ($_GET["gender"] != "")) {
  $gender = $_GET["gender"];
  $search_gender = 1;
  }

但是，要摆脱所有这些ifs ....

 if (($search_name==1) AND ($search_country==1) AND ($search_city==1) AND ($search_age==1) AND ($search_gender==1) ){

}else if(($search_name==1) AND ($search_country==0) AND ($search_city==0) AND ($search_age==0) AND ($search_gender==0) ){

 }

.....等等...... = 32如果陈述

我使用了这种格式的开关案例功能：

 switch($search_name . $search_country . $search_city . $search_age . $search_gender) {
 case 11111 : 
  $query=mysql_query("SELECT  * FROM users WHERE `username` LIKE '%" . $name .  "%' OR  `country` LIKE '%" . $country .  "%' OR `city` LIKE '%" . $city .  "%' OR `birth_month` LIKE '%" . $age .  "%' OR `sex` LIKE '%" . $gender .  "%' ");
  $allow_querry = true;
   break;
    case 11110 :  
    $query=mysql_query("SELECT  * FROM users WHERE `username` LIKE '%" . $name .  "%' OR  `country` LIKE '%" . $country .  "%' OR `city` LIKE '%" . $city .  "%' OR `birth_month` LIKE '%" . $age .  "%' ");
    $allow_querry = true;
   break;

等32例

您是否知道其他方法可以让它看起来更漂亮或者更容易编写，假设我有数百种组合？

Answer 1

假设您不需要允许and / or变体，只需构建一个选项数组，最终sql崩溃：

$options = array();
if( ... do city search) {
   $options[] = '`city` LIKE "$name"';
}
if( ... do country search ) {
   $options[] = '`country` LIKE "$name"';
}
etc...

$where_clause = implode(' OR ', $options);

$sql = "SELECT ... WHERE $where_clause";

请注意，您很容易受到sql injection attacks的攻击。</ p>

或者，您也可以使用fulltext搜索，只搜索您需要的特定字段：

if (...city search) {
   $fields[] = 'city';
}
etc...
$field_list = implode(', ', $fields);

$sql = "SELECT ... WHERE MATCH($fields) AGAINST '$name'"

PHP声明if语句的排列

1 个答案: