Spring安全性UserDetailsS​​ervice无法正常工作

时间:2016-08-26 12:57:56

标签: java spring spring-security spring-boot

好的,伙计们,我希望你能帮助我,这是我的最后一次尝试。我对这个春天的安全世界很陌生,我不能让它发挥作用。我尝试了很多东西,接着是许多教程而没有。

正如您在标题中看到的那样,问题是使自定义用户详细信息服务正常工作。它只是没有登录,似乎没有调用customuserdetails服务,因为sysouts没有在控制台中显示...

它在内存功能方面具有弹簧安全性的魅力。以下是我的代码。

Spring Security Config:

@Configuration
@EnableWebSecurity
@ComponentScan(basePackageClasses = CustomUserDetailsService.class)
public class SecurityConfig extends WebSecurityConfigurerAdapter {

@Autowired
UserDetailsService userDetailsService;

@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
    //auth.inMemoryAuthentication().withUser("ram").password("ram123").roles("ADMIN");
    auth.userDetailsService(userDetailsService).passwordEncoder(passwordencoder());
}

@Override
public void configure(WebSecurity web) throws Exception {
  web
    .ignoring()
       .antMatchers("/bower_components/**", "/resources/**", "/img/**"); // #3
}

@Override
protected void configure(HttpSecurity http) throws Exception {
    http.httpBasic().and().csrf().disable()
    .authorizeRequests()
      .antMatchers("/", "/home", "/call").permitAll() // #4
      .antMatchers("/resource", "/video").hasRole("USER") // #6
      .anyRequest().authenticated();
}

@Bean(name="passwordEncoder")
public PasswordEncoder passwordencoder(){
    return new BCryptPasswordEncoder();
}

}

CustomUserDetailsS​​ervice

@Service("customUserDetailsService")
public class CustomUserDetailsService implements UserDetailsService{

private UserService userService;

@Override
public UserDetails loadUserByUsername(String ssoId)
        throws UsernameNotFoundException {
    User user = userService.findByUsername(ssoId);
    System.out.println("User : "+user);
    if(user==null){
        System.out.println("User not found");
        throw new UsernameNotFoundException("Username not found");
    }
        return new org.springframework.security.core.userdetails.User(user.getUsername(), user.getPassword(), 
             user.isEnabled(), true, true, true, getGrantedAuthorities(user));
}


private List<GrantedAuthority> getGrantedAuthorities(User user){
    List<GrantedAuthority> authorities = new ArrayList<>();

    authorities.add(new SimpleGrantedAuthority(user.getRole()));

    System.out.print("authorities :"+authorities);
    return authorities;
}
}

初始化程序类

@SpringBootApplication
@EnableWebSocket
public class One2OneCallApp implements WebSocketConfigurer {

@Bean
public CallHandler callHandler() {
  return new CallHandler();
}

@Bean
public UserRegistry registry() {
  return new UserRegistry();
}

@Bean
public KurentoClient kurentoClient() {
  return KurentoClient.create();
}

@Bean
public UiApplication uiApplication(){
  return new UiApplication();
}

@Bean
public CustomUserDetailsService customUserDetailsService(){
  return new CustomUserDetailsService();
}

@Bean
public SecurityConfig securityConfig(){
  return new SecurityConfig();
}

@Bean
public EncryptPassword encryptPassword(){
  return new EncryptPassword();
}

@Override
public void registerWebSocketHandlers(WebSocketHandlerRegistry   registry) {
  registry.addHandler(callHandler(), "/call");
}

public static void main(String[] args) throws Exception {
  System.out.println("Iniciando");  
  new SpringApplication(One2OneCallApp.class).run(args);    
}

}

我还测试了与数据库的通信,它工作得很好。我正在寻求任何帮助。抱歉英语不好。谢谢大家!

编辑:在下面回答我自己的问题。

4 个答案:

答案 0 :(得分:0)

SecurityConfig课程中:

@Autowired
CustomUserDetailsService customUserDetailsService;

@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(customUserDetailsService);
}

答案 1 :(得分:0)

更改

@Autowired
UserDetailsService userDetailsService;

@Autowired
CustomUserDetailsService userDetailsService;

此外,在您的web / socket配置中导入安全配置并在那里移动组件扫描,而不是在安全性上

@ComponentScan(basePackageClasses = CustomUserDetailsService.class)
@Import(value = { SecurityConfig.class })
public class WebConfig extends WebMvcConfigurerAdapter { /*...*/ }

答案 2 :(得分:0)

您正在安全配置中设置hasRole(“”),并且您正在使用权限进行身份验证。

而不是使用.antMatchers(“/ resource”,“/ video”)。hasRole(“USER”)   使用.antMatchers(“/ resource”,“/ video”)。hasAuthority(“USER”)

答案 3 :(得分:-3)

我最终坚持使用内置的内存验证,只是为了我必须做的演示。我认为我的问题与弹簧启动和我的应用程序中的初始化有关。