我正在开发一个数学测验应用程序,它会从array
输入中随机生成问题,但它会无限期地继续,我不得不在提出10个问题之后停止生成问题,但我不知道怎么可以帮助我。我用这个
private void selectQuestion(){
answerTxt.setText("?");
operand1=getOperand1();
operand2=getoperand2();
question.setText(operand1 + "*" +operand2);
answer=operand1 * operand2;
}
private int getOperand1() {
operand1=random.nextInt(level2op1.length);
return operand1;
}
private int getOperand2() {
operand2=random.nextInt(level2op2.length);
return operand2;
}
@Override
public void onClick(View view) {
if (view.getId() == R.id.btn_one || view.getId() == R.id.btn_two
|| view.getId() == R.id.btn_three || view.getId() == R.id.btn_four
|| view.getId() == R.id.btn_five || view.getId() == R.id.btn_six
|| view.getId() == R.id.btn_seven || view.getId() == R.id.btn_eight
|| view.getId() == R.id.btn_nine || view.getId() == R.id.btn_zero) {
if (answer <= 9) {
Log.e("tag","ans : " + answer);
//get number from tag
int enteredNum = Integer.parseInt(view.getTag().toString());
if (answerTxt.getText().toString().endsWith("?"))
answerTxt.setText("" + enteredNum);
if (enteredNum == answer) {
response.setImageResource(R.drawable.tick);
response.setVisibility(View.VISIBLE);
} else {
response.setImageResource(R.drawable.cross);
response.setVisibility(View.VISIBLE);
}
selectQuestion();
}
else if (answer > 9) {
Log.e("tag","ans : " + answer);
int enteredNum = Integer.parseInt(view.getTag().toString());
enteredInput = enteredInput * 10 + enteredNum;
answerTxt.setText("" + enteredInput);
Log.e("tag","enteredInput : " + enteredInput);
if (enteredInput == answer) {
Log.e("tag","correct : " );
response.setImageResource(R.drawable.tick);
response.setVisibility(View.VISIBLE);
selectQuestion();
}
else if (enteredInput > 9) {
Log.e("tag","wrong : " );
response.setImageResource(R.drawable.cross);
response.setVisibility(View.VISIBLE);
selectQuestion();
}
}
}
else if (view.getId() == R.id.btn_clr)
{
answerTxt.setText("?");
enteredInput=0;
}
}
答案 0 :(得分:0)
要停止方法执行,我们使用return
关键字。
执行方法10次使用:
for (int i = 0; i < 10; i++) {
method();
}