Question

我有一张桌子，我正在尝试使用我们的打开的门票和他们收到的最后一次跟进，下面的列，这称为“glpi_plugin_ns_followup”：

id[int(11)], entities_id[int(11)], name[varchar(255)], date[datetime], closedate[datetime], solvedate[datetime], date_mod[datetime], users_id_lastupdater[int(11)], status[int(11)], users_id_recipient[int(11)], requesttypes_id[int(11)], content, urgency[int(11)], impact[int(11)], priority[int(11)], itilcategories_id[int(11)], type[int(11)], solutiontypes_id[int(11)], solution, global_validation[int(11)], slas_id[int(11)], slalevels_id[int(11)], due_date[datetime], begin_waiting_date[datetime], sla_waiting_duration[int(11)], waiting_duration[int(11)], close_delay_stat[int(11)], solve_delay_stat[int(11)], takeintoaccount_delay_stat[int(11)], actiontime[int(11)], is_deleted[tinyint(1)], locations_id[int(11)], validation_percent[int(11)]

我从中拉出的表是glpi_tickets和glpi_ticketfollowups

glpi_tickets

id[int(11)], tickets_id[int(11)], date[datetime], users_id[int(11)], content[longtext], is_private[tinyint(11)], requesttypes_id[int(11)]

glpi_ticketfollowups

TRUNCATE glpi_plugin_ns_followup;
INSERT INTO glpi_plugin_ns_followup (ticket_number, datetime_created, requester, title, description)
SELECT Id, date, users_id_recipient, name, content FROM glpi.glpi_tickets
WHERE is_deleted = 0 and status !=6 and status !=5;

这三个公共标识符如下：

glpi_tickets = id

glpi_ticketfollowups = tickets_id

glpi_plugin_ns_followup = ticket_number

我设法使用以下查询插入前五列：

UPDATE glpi_plugin_ns_followup 
    SET followup_datetime = (SELECT date from glpi_ticketfollowups where glpi_ticketfollowups.tickets_id = glpi_plugin_ns_followup.ticket_number),
        last_followup = (SELECT content from glpi_ticketfollowups where glpi_ticketfollowups.tickets_id = glpi_plugin_ns_followup.ticket_number),
        technician_user = (SELECT users_id from glpi_ticketfollowups where glpi_ticketfollowups.tickets_id = glpi_plugin_ns_followup.ticket_number)

但是我很难用相关更新填写最后3列，到目前为止我已经尝试使用此代码，但它不起作用：

Error Code: 1242. Subquery returns more than 1 row

这给了我答复：

UPDATE glpi_plugin_ns_followup 
SET followup_datetime = (SELECT max(date) from glpi_ticketfollowups where glpi_ticketfollowups.tickets_id = glpi_plugin_ns_followup.ticket_number GROUP BY tickets_id)

我应该尝试更新多行，或者错误可能是因为每张票有多个后续。我有一种感觉，我可能会从完全错误的角度出发。如果有人可以帮助我并让我回到正确的轨道上，那将非常感激。

如果需要，我可以提供样本数据，但需要一段时间来收集和审查它; - ）

编辑：根据卡米尔对max（）的建议，我设法让日期字段起作用：

GROUP BY t.id;

但是，我无法让它为内容或技术人员用户工作，如果我可以在最后一次为故障单添加后续操作时提取最新的日期/时间，我是否可以修改任何内容以提取内容和技术员_用户？ / p>

EDIT2：尝试在初始解决方案的最后添加TRUNCATE glpi_plugin_ns_followup; INSERT INTO glpi_plugin_ns_followup (ticket_number, datetime_created, requester, title, description, followup_datetime, last_followup, technician_user) SELECT t.id, t.date, t.users_id_recipient, t.name, t.content, tf.datetime, tf.content, tf.users_id FROM glpi.glpi_tickets t LEFT JOIN (SELECT max(date) as datetime, content, users_id, tickets_id FROM glpi_ticketfollowups GROUP BY tickets_id) tf ON t.id = tf.tickets_id WHERE t.is_deleted = 0 and t.status NOT IN (5,6) GROUP BY t.id;，但它没有使用最新的门票跟进。

EDIT3：尝试过以下内容，它会输入正确的日期/时间但内容错误

{{1}}

由于 iFr4g

Answer 1

您可以将这两个语句合并为一个且仅发出INSERT命令。但是，如果使用条件glpi_tickets获取的glpi_ticketfollowups中存在多个匹配行，则会将您的行与t.id = tf.tickets_id相乘。

我添加了LEFT JOIN并略微更改了WHERE子句以节省一些编码。

INSERT INTO glpi_plugin_ns_followup (ticket_number, datetime_created, requester, title, description, followup_datetime, last_followup, technician_user)
SELECT 
  t.id, t.date, t.users_id_recipient, t.name, t.content,
  tf.date, tf.content, tf.users_id
FROM 
  glpi.glpi_tickets t
  LEFT JOIN glpi_ticketfollowups tf ON
    t.id = tf.tickets_id
WHERE 
  t.is_deleted = 0 
  and t.status NOT IN (5,6)

如果目标表中每个glpi_tickets表只需要一行，那么您要查找的是每个票证只能从glpi_ticketfollowups获取一行的方法。这可以通过添加GROUP BY子句并选择获取一个值的适当逻辑来实现，例如：max()或min()。请记住，发布超过3个值的聚合函数不会从一行获得结果，而是从整个数据集中获得聚合结果。这可以通过您开始的方式来避免 - 通过添加LIMIT子句来插入和更新。

评论后编辑：

由于您需要为每张故障单进行最后一次跟进，并且您确定每张故障单的日期都是唯一的，您可以自行加入计算glpi_ticketfollowups中每张故障单的最大日期，然后LEFT JOIN你的glpi_tickets表：

INSERT INTO glpi_plugin_ns_followup (ticket_number, datetime_created, requester, title, description, followup_datetime, last_followup, technician_user)
SELECT 
  t.id, t.date, t.users_id_recipient, t.name, t.content,
  tf.date, tf.content, tf.users_id
FROM 
  glpi.glpi_tickets t
  LEFT JOIN (
    SELECT allf.tickets_id, allf.date, allf.content, allf.users_id
    FROM glpi_ticketfollowups allf
    INNER JOIN (
      SELECT tickets_id, MAX(date) AS date
      FROM glpi_ticketfollowups
      GROUP BY tickets_id
      ) lastf ON
        allf.tickets_id = lastf.tickets_id
        AND allf.date = lastf.date
    ) tf ON
    t.id = tf.tickets_id
WHERE 
  t.is_deleted = 0 
  and t.status NOT IN (5,6)

使用来自另外两个表的选定数据填充一个表

1 个答案: