使用来自不同表的其他字段返回前10个MYSQL查询结果

Question

我需要根据收入增长返回前10名客户，同时还要显示订单数量和订单总重量。

首先，我们有客户表，用于存储客户帐户。 其次，我们有发票表，它存储每个订单的收入。这将用于获得前十名客户，因为他们按收入排名。 最后，我有订单表，它存储有关订单的其他详细信息，例如重量。

我试过了：

SELECT (c.account_number as Account, c.customer_name as Name, SUM(i.total_charge) as Revenue, COUNT(s.order) as NumberOfOrder, SUM(s.tot_weight) as Weight)
FROM t_customer as c
JOIN t_invoice as i ON c.account_number = i.account_number
JOIN t_shipment as s ON c.account_number = s.shipper_account 
WHERE s.ship_date BETWEEN '2016-08-01' AND '2016-08-31'
GROUP BY c.account_number
ORDER BY SUM(i.total_charge) DESC LIMIT 10

我认为我有正确但它只返回SQL错误（1241）：操作数应该是1列。谢谢你的帮助。

Answer 1

不要在您的选择中添加括号。

SELECT c.account_number as Account, c.customer_name as Name, SUM(i.total_charge) as Revenue, COUNT(s.order) as NumberOfOrder, SUM(s.tot_weight) as Weight
FROM t_customer as c
JOIN t_invoice as i ON c.account_number = i.account_number
JOIN t_shipment as s ON c.account_number = s.shipper_account 
WHERE s.ship_date BETWEEN '2016-08-01' AND '2016-08-31'
GROUP BY c.account_number
ORDER BY SUM(i.total_charge) DESC LIMIT 10

希望它会有所帮助。